[From Bill Powers (2006.12.29.0930 MST)]
I said (2006.12.23) that
-dk(k - jw)
o = -------------
k^2 + w^2The cosine of the phase angle of o relative to d is -d(k^2)/(w^2 + k^2)
If I'd done it right, the expression would have been
cos(phase angle) = k/SQRT(w^2 + k^2)
I'm pretty rusty at this sort of thing.
Best,
Bill P.