[From Bruce Abbott (960106.1425 EST)]
I just realized that I could have done a little better job of presenting the
equivalent formulas for Killeen's model in lines 5 and 6 of my table, which
will bring out the parallel with the control model even more strongly. On
line 5, make the following substitution:
change g = v*h/s to g = v*Y/s
This makes g a constant, as in the control model. On line 6,
change B = g*R to B = g*e*R,
which compares to B = g*e for the control model. The table will look like
this after the changes:
Control model Killeen's model Equivalent formula
···
-----------------------------------------------------------------------
(1) F = F + (m*R - M)*dt d = d + (M - m*R)*dt F = F + (m*R - M)*dt
(2) p = F p = F
(3) e = Fr - p e = Fr - p
(4) h = Y*d h = Y*e
(5) g = constant a = v*h g = v*Y/s
(6) B = g*e B = a*R/s B = g*e*R
(7) R = B/n R = B/n R = B/n
-----------------------------------------------------
The "equivalent equations" on lines 5 and 6 are not strictly equivalent to
Killeen's on lines 5 and 6, but their combined effects are mathematically
equivalent.
Regards,
Bruce