Looking at the Power Law through Laputasian Glasses

[From Rick Marken (2016.08.12.1055)]

image298.png

image299.png

···

Erling Jorgensen (2016.0812 1135 EDT)

EJ: Hi Rick,

Would you respond to the following part of Bruce’s post? This is the part where I keep getting hung up, in trying to follow these postings.

Because velocity (decomposed into x and y components) appears in D (along with acceleration, similarly decomposed), you have velocity (and its derivative) on both sides of your equation, V = D1/3 *R1/3. Which is why solving it for V as you do makes little sense…

RM: Solving for V in my equation may make little sense to Bruce but it makes sense to my computer. I’ll demonstrate this by first taking the log of both sides of the equation that Bruce finds senseless:

log (V) = .33log(D) + .33 log(R)

RM: This is now a linear equation and it implies that if we did a multiple linear regression analysis with log(D) and log(R) as the predictor variables and log (V) as the criterion variable, the regression should find the b weights for log(D) and log(R) to be .33 and the R^2 value to be 1.0 (indicating that R and D account for all the variability in V). And, indeed, this is what is found (using Excel to do the regression) for all movement patterns except a straight line.

RM: If log (D) is left out of the regression, so that the regression is of the form:

log (V) = a + b*log(R)

then the value you get for b – the power law coefficient – depends on the nature of the movement pattern. If the movement pattern is fairly circular (or elliptical), like this:

the regression will give you an estimate of b that’s close to .33. For the movement pattern above, b was .37 and R^2 was .85. A more jagged movement pattern, like this:

gives a very different estimate for b; in this case b = .60 and the R^2 is .8.

RM: My model assumes that these different estimates of b result from failure to include log(D) in the regressions and have nothing to do with differences in the way these patterns were produced. Evidence that this is the case is that when log(D) is included in both regressions the estimate of the coefficient of both log(R) and log (D) is .33 in both movement patterns above and the R^2 is 1.0.

RM: By the way, these are real movement patterns, produced by yours truly, and I will soon have a spreadsheet demo that lets you put in your own movement patterns to see how the estimates of b change with the pattern produced.

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Erling Jorgensen (2016.08.12 1455 EDT)]

Hi Rick,

I still don’t understand how log(D), which includes V components & V-derivative (i.e., acceleration) components, can serve as a predictor variable of log(V) as a criterion variable. V ends up predicting itself (in part), which is the essence of a tautology. What am I missing, or what are you missing as far as not understanding my question?

All the best,

Erling

Richard Marken rsmarken@gmail.com 8/12/2016 1:56 PM >>>

[From Rick Marken (2016.08.12.1055)]

Erling Jorgensen (2016.0812 1135 EDT)

EJ: Hi Rick,

Would you respond to the following part of Bruce’s post? This is the part where I keep getting hung up, in trying to follow these postings.

Because velocity (decomposed into x and y components) appears in D (along with acceleration, similarly decomposed), you have velocity (and its derivative) on both sides of your equation, V = D1/3 *R1/3. Which is why solving it for V as you do makes little sense…

RM: Solving for V in my equation may make little sense to Bruce but it makes sense to my computer. I’ll demonstrate this by first taking the log of both sides of the equation that Bruce finds senseless:

log (V) = .33log(D) + .33 log(R)

RM: This is now a linear equation and it implies that if we did a multiple linear regression analysis with log(D) and log(R) as the predictor variables and log (V) as the criterion variable, the regression should find the b weights for log(D) and log(R) to be .33 and the R^2 value to be 1.0 (indicating that R and D account for all the variability in V). And, indeed, this is what is found (using Excel to do the regression) for all movement patterns except a straight line.

RM: If log (D) is left out of the regression, so that the regression is of the form:

log (V) = a + b*log(R)

then the value you get for b – the power law coefficient – depends on the nature of the movement pattern. If the movement pattern is fairly circular (or elliptical), like this:

image299.png

the regression will give you an estimate of b that’s close to .33. For the movement pattern above, b was .37 and R^2 was .85. A more jagged movement pattern, like this:

image298.png

gives a very different estimate for b; in this case b = .60 and the R^2 is .8.

RM: My model assumes that these different estimates of b result from failure to include log(D) in the regressions and have nothing to do with differences in the way these patterns were produced. Evidence that this is the case is that when log(D) is included in both regressions the estimate of the coefficient of both log(R) and log (D) is .33 in both movement patterns above and the R^2 is 1.0.

RM: By the way, these are real movement patterns, produced by yours truly, and I will soon have a spreadsheet demo that lets you put in your own movement patterns to see how the estimates of b change with the pattern produced.

Best

Rick

···


Richard S. Marken

“The childhood of the human race is far from over. We have a long way to go before most people will understand that what they do for others is just as important to their well-being as what they do for themselves.” – William T. Powers

  NOTICE: This e-mail communication (including any attachments) is CONFIDENTIAL and the materials contained herein are PRIVILEGED and intended only for disclosure to or use by the person(s) listed above. If you are neither the intended recipient(s), nor a person responsible for the delivery of this communication to the intended recipient(s), you are hereby notified that any retention, dissemination, distribution or copying of this communication is strictly prohibited. If you have received this communication in error, please notify me immediately by using the "reply" feature or by calling me at the number listed above, and then immediately delete this message and all attachments from your computer. Thank you.

[From Rick Marken (2016.08.12.2150)]

image298.png

image299.png

···

Erling Jorgensen (2016.08.12 1455 EDT)–

EJ: I still don’t understand how log(D), which includes V components & V-derivative (i.e., acceleration) components, can serve as a predictor variable of log(V) as a criterion variable.

RM: I don’t understand why this is a problem. Is there a new math rule that I don’t know about? Power law researchers use the following two equations to find the instantaneous tangential velocity (V) and instantaneous radial curvature (R) of a movement pattern:

V = (X2+Y2 )1/2

      </sup>

R = [(X2+Y2 )3/2]/|dXd2Y-d2XdY|

It turns out that V2 – (X2+Y2 ) – is part of the numerator of R. So I think it is perfectly correct (and my math teacher son concurs) to write:

R = [(V2)3/2]/|dXd2Y-d2XdY|

And from there it’s a pretty straight shot to:

V = D1/3 *R1/3

and

log(V) = .33log(D) + .33log(R)

EJ: V ends up predicting itself (in part), which is the essence of a tautology. What am I missing, or what are you missing as far as not understanding my question?

RM: If you think that my formula for V as a function of R and D – V = D1/3 R1/3 – is a tautology (which it’s not) then you would also have to think that the PCT formula for output, o, as a function of disturbance, d, and reference, r – o = r - 1/k.fd-- is a tautology. After all, the PCT formula for o as a function of r and d is derived from the following:

p = k.f*o - d

o = k.s*(r-p)

and substituting k.f*o + d for p in the second equation we get

o = k.s*(r- k.f*o - d)

and from there it’s a pretty straight shot to

o = r - 1/k.f*d

RM: Since o is a “component” of d, per the top equation, d = p/(k.f o), the PCT formula for o as a function of r and d --o = r - 1/k.fd, one of the most important formulas in PCT since it shows that the output of a control system is not a function of input – is a tautology. My kind of tautology!

RM: I think this tautology idea is something that was made up to protect the power law from the PCT explanation of why it is observed.

RM: On that note maybe you could explain what is wrong with my PCT model of the power law as it is found in intentionally produced curved movement. Here it is again:

RM: What’s wrong with this model?? And please don’t say that it has something to do with my selection of the controlled variable unless you can suggest what the controlled variable should be and explain why a different controlled variable would make a difference.That criticism of the model is as ridiculous as the tautology criticism of the formula: V = D1/3 *R1/3.

RM: It would sure by nice if we could start talking about PCT explanations of behavior again. Maybe you can get the ball rolling, Erling!

Best

Rick

All the best,

Erling

Richard Marken rsmarken@gmail.com 8/12/2016 1:56 PM >>>

[From Rick Marken (2016.08.12.1055)]

  NOTICE: This e-mail communication (including any attachments) is CONFIDENTIAL and the materials contained herein are PRIVILEGED and intended only for disclosure to or use by the person(s) listed above. If you are neither the intended recipient(s), nor a person responsible for the delivery of this communication to the intended recipient(s), you are hereby notified that any retention, dissemination, distribution or copying of this communication is strictly prohibited. If you have received this communication in error, please notify me immediately by using the "reply" feature or by calling me at the number listed above, and then immediately delete this message and all attachments from your computer. Thank you.


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Erling Jorgensen (2016.0812 1135 EDT)

EJ: Hi Rick,

Would you respond to the following part of Bruce’s post? This is the part where I keep getting hung up, in trying to follow these postings.

Because velocity (decomposed into x and y components) appears in D (along with acceleration, similarly decomposed), you have velocity (and its derivative) on both sides of your equation, V = D1/3 *R1/3. Which is why solving it for V as you do makes little sense…

RM: Solving for V in my equation may make little sense to Bruce but it makes sense to my computer. I’ll demonstrate this by first taking the log of both sides of the equation that Bruce finds senseless:

log (V) = .33log(D) + .33 log(R)

RM: This is now a linear equation and it implies that if we did a multiple linear regression analysis with log(D) and log(R) as the predictor variables and log (V) as the criterion variable, the regression should find the b weights for log(D) and log(R) to be .33 and the R^2 value to be 1.0 (indicating that R and D account for all the variability in V). And, indeed, this is what is found (using Excel to do the regression) for all movement patterns except a straight line.

RM: If log (D) is left out of the regression, so that the regression is of the form:

log (V) = a + b*log(R)

then the value you get for b – the power law coefficient – depends on the nature of the movement pattern. If the movement pattern is fairly circular (or elliptical), like this:

the regression will give you an estimate of b that’s close to .33. For the movement pattern above, b was .37 and R^2 was .85. A more jagged movement pattern, like this:

gives a very different estimate for b; in this case b = .60 and the R^2 is .8.

RM: My model assumes that these different estimates of b result from failure to include log(D) in the regressions and have nothing to do with differences in the way these patterns were produced. Evidence that this is the case is that when log(D) is included in both regressions the estimate of the coefficient of both log(R) and log (D) is .33 in both movement patterns above and the R^2 is 1.0.

RM: By the way, these are real movement patterns, produced by yours truly, and I will soon have a spreadsheet demo that lets you put in your own movement patterns to see how the estimates of b change with the pattern produced.

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We have a long way to go before most people will understand that what they do for others is just as important to their well-being as what they do for themselves.” – William T. Powers

[Martin Taylor 2016.08.13.12.25]

[From Rick Marken (2016.08.12.2150)]

<sup>Actually, ![SpeedFormula.jpg|191x50](upload://7T7uJxDMeSpjWCa9A0FDkWDazI.jpeg)</sup>

Actually, your math teacher some missed a beat here. The

differentiation is by some parameter that specifies a distance along
the curve, and time doesn’t do that unless you pre-specify V as a
function of time. The formula for curvature (1/R) is actually

![curvatureFormulaByS.jpg|245x98](upload://4dWi0tOjX84Gux9EM2qYyNbfrXy.jpeg)

Notice the "s" parameter, which is simply distance along the curve.

That’s the simplest parameter, but you could use any other that
uniquely specifies a location along the curve. Time doesn’t come
into the computation of curvature (or radius of curvature) at all,
because curvature isn’t a function of time.

If you have prespecified some V, which is ds/dt, as a function of

either s or t, you can connect the two formulae, but you can’t do it
until after you specify V. Your specified V(t) can be anything,
provided it is never zero nor negative, and is continuous. If you
have specified V (= ds/dt), you can rewrite the curvature formula
using differentiation with respect to time, since dx/dt = dx/ds *
ds/dt = V*dx/ds, and d2x/dt = d(dx/dt)/dt = V2 d(dx/ds)/ds
= V2
d2x/ds2 . But I emphasize that
this makes sense only if you have prespecified your V. (Actually,
the “always positive” restriction is required only to make t unique
for any value of s. The derivatives don’t need it).

Making these substitutions, you have

![curvatureFormulaWithVs.jpg|296x98](upload://468awB4mAMKc6x1mhlqhjANfs0.jpeg)

Eliminating the V<sup>3</sup> from numerator and denominator gives

you the formula you originally used

![curvatureFormulaLeibnitz.jpg|245x98](upload://miDgbNUrNeBHkHCd47n5FGE61ev.jpeg)

This formula works only because you prespecified V(t) (or V(s)).

Your chosen V(t) (or V(s)) is entirely arbitrary so long as it is
never negative or zero and can be differentiated everywhere.
Therefore you cannot use these formulae to determine V. Please ask
your math teacher son to check the accuracy of what I say.

Which it is.

Not at all. It's entirely different.

No tautology at all. In the control loop formula, you can

independently specify r, k, f and d. A value of o pops out. In your
V formula, you cannot separately specify D and R, because D is a
function of V ( D = V3/R), the same function (V3 )
that you are trying to estimate by using the equation V = D1/3*R1/3.

No such explanation has yet been suggested in public (AFAIK).

OK. What's wrong with that model is that time, and therefore

velocity, is not represented in the model. Any velocity that appears
on the output is dependent on velocities of the reference in x and
y. Hence the model cannot be relevant to the question of why the
velocity is so often observed to vary as R1/3 , and under
other conditions does not. All your model does is shove the question
up a level so that we must ask why the reference signal has those
properties.

Yes, just as (non) ridiculous -- i.e. accurate.

Indeed it would. How about starting by suggesting another

experiment, different from mine, to narrow the search for the
controlled variable(s)? Or failing that, how about suggesting
experiments that might follow any one of the three possible results
of my proposed experiment? All we need is to recognize that your
model might possibly represent the output stage of a model that
explains the power law under circumstances where x and y can be
perceived and controlled independently. First we need to know what
perception(s) that effective model might control.

Martin

···

Erling Jorgensen (2016.08.12 1455 EDT)–

                EJ: I still don't understand how log(D), which

includes V components & V-derivative (i.e.,
acceleration) components, can serve as a predictor
variable of log(V) as a criterion variable.

            RM: I don't understand why this is a problem. Is

there a new math rule that I don’t know about? Power law
researchers use the following two equations to find the
instantaneous tangential velocity (V) and instantaneous
radial curvature (R) of a movement pattern:

                V

= (X2+Y2 ) 1/2

                </sup>
      </sup>



                R

= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V2 – (X2+Y2 )
is
part of the numerator of R. So I think it is perfectly
correct (and my math teacher son concurs) to write:

              R

= [(V2)3/2]/|dXd2Y-d2 XdY|

                  And from there it's a

pretty straight shot to:

                V =

D1/3 *R1/3

                </sup>

and

              log(V)

= .33log(D) + .33log(R)

                EJ: V ends up predicting itself (in part), which

is the essence of a tautology. What am I missing,
or what are you missing as far as not understanding
my question?

            RM:  If you think that my formula for V as a function

of R and D – V
= D1/3 *R1/3
is a tautology (which it’s not)

            then you would also have to think that the PCT

formula for output, o, as a function of disturbance, d,
and reference, r – o = r - 1/k.f*d-- is a tautology.

            After all, the PCT formula for o as a function of r

and d is derived from the following:

p = k.f*o - d

o = k.s*(r-p)

            and substituting  k.f*o + d for p in the second

equation we get

o = k.s*(r- k.f*o - d)

and from there it’s a pretty straight shot to

o = r - 1/k.f*d

            RM: Since o is a "component" of d, per the top

equation, d = p/(k.f o), the PCT formula for o as a
function of r and d --o = r - 1/k.f
d, one of the most
important formulas in PCT since it shows that the output
of a control system is not a function of input – is a
tautology. My kind of tautology!

            RM: I think this tautology idea is something that was

made up to protect the power law from the PCT
explanation of why it is observed.

            RM: On that note maybe you could explain what is

wrong with my PCT model of the power law as it is found
in intentionally produced curved movement. Here it is
again:

RM: What’s wrong with this model??

            And please don't say that it has something to do

with my selection of the controlled variable unless you
can suggest what the controlled variable should be and
explain why a different controlled variable would make a
difference.That criticism of the model is as ridiculous
as the tautology criticism of the formula: V
= D1/3 *R1/3.

            RM: It would sure by nice if we could start talking

about PCT explanations of behavior again. Maybe you can
get the ball rolling, Erling!

[From Rick Marken (2016.08.13.1145)]

SpeedFormula.jpg

···

Martin Taylor (2016.08.13.12.25)

MT: Actually,

RM: Correct. My X’s and Y’s should have dots over them.

MT: Actually, your math teacher some missed a beat here. The

differentiation is by some parameter that specifies a distance along
the curve, and time doesn’t do that unless you pre-specify V as a
function of time. The formula for curvature (1/R) is actually

RM: Not Correct. The X and Y in the numerator of R should have a dot over them, as they should in the expression for V. They are the same derivative; a change in position over time, dt. So my derivation is correct and your is not.

MT: OK. What's wrong with that model is that time, and therefore

velocity, is not represented in the model. Any velocity that appears
on the output is dependent on velocities of the reference in x and
y.

RM: Why is that wrong?

MT: Hence the model cannot be relevant to the question of why the

velocity is so often observed to vary as R1/3 , and under
other conditions does not.

RM: So you don’t like the idea that variations in input (including variations in the velocity of these inputs) are caused by variations in the reference for these inputs? That’s actually the way PCT explains observed variations in movement. What’s your model?

MT: All your model does is shove the question

up a level so that we must ask why the reference signal has those
properties.

RM: My model is a PCT explanation of movement control. It has worked in other contexts and it works in this one. The model assumes that the variations in the reference for the position of the moved object (such as the pencil in this case) are caused by higher level systems. And it would be nice to study how and why higher order systems vary these references. But the model, as it stands, is meant to account for the observation of the power law in curved movement; and the model does that (as I will demonstrate in my experiments).

MT: Indeed it would. How about starting by suggesting another

experiment, different from mine, to narrow the search for the
controlled variable(s)?

RM: I am developing experiments that will test the model above.

MT: First we need to know what

perception(s) that effective model might control.

RM: You first have to come up with a hypothesis about what the controlled variable is in this situation. I’ve already done (and published – see, for example, Marken, R. S. (1991) Degrees of Freedom in Behavior. Psychological Science, 2, 92 - 100) quite a lot of research showing that the controlled variable in control of 2_D movement is the X and Y position of the moved object (like a cursor). So I’m rather confident that my model is controlling the variable that people control when they make two dimension movements. But this will be further confirmed, I’m sure, when the model behaves exactly like the people in my experiments.

            RM: I don't understand why this is a problem. Is

there a new math rule that I don’t know about? Power law
researchers use the following two equations to find the
instantaneous tangential velocity (V) and instantaneous
radial curvature (R) of a movement pattern:

                V

= (X2+Y2 ) 1/2

                </sup>

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2XdY|

It turns out that V2 – (X2+Y2 )
is
part of the numerator of R. So I think it is perfectly
correct (and my math teacher son concurs) to write:

              R

= [(V2)3/2]/|dXd2Y-d2 XdY|

            RM: On that note maybe you could explain what is

wrong with my PCT model of the power law as it is found
in intentionally produced curved movement. Here it is
again:

RM: What’s wrong with this model??

            RM: It would sure by nice if we could start talking

about PCT explanations of behavior again. Maybe you can
get the ball rolling, Erling!

RM: I would sure like to see your alternative model. Without it I have no idea what the heck you’re trying to test with your experiment. .

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Bruce Abbott (2016.08.13.1915 EDT]

Rick Marken (2016.08.12.1010) –

My Dear Laputasian Friend,

The paper you sent to the Royal Society a fortnight ago, On the Mathematical Necessity of the Power Law Relating Velocity to Radius of Curvature, has been carefully studied by our reviewers. I am sorry to convey to you our decision not to publish in The Annals of the Royal Society. Rather than present each reviewer’s comments separately (since they are largely redundant), I shall summarize the reasons for this rejection.

In your paper you present the standard formula used by Power-Law researchers to compute tangential velocity V as follows:

image00316.png

Here, X and Y are the x- and y-axis Cartesian coordinates of a given point along the curve; Xdot and Ydot are the respective first derivatives, i.e., velocities in the X and Y directions. Next you present the formula used to compute the radius of curvature R:

image484.png

You notice that the numerator of this equation is equal to V3, and decide to represent the denominator as D. Thus,

R = V3/D.

Our mathematicians found no errors up to this point. However, in your next step you solve this equation for V:

V = D1/3R1/3

Whether this formula is valid for a particular purpose depends on the purpose. If you are using it, given D and R, to find what the value of V must have been when R and D were computed, this equation will do just fine. But if you are using it to predict V from D and R, the formula is not valid for that purpose. In fact, given that you know the values of D and R, the formula provides an exact value for V. However,

You go on to take the logarithms of both sides:

Log(V) = a Log(D) + β Log®

You then state the following, based on your spreadsheet:

Log(V) = 1/3 Log(D) + 1/3 Log®, R-sq = 1.0.

From this you conclude the following:

The particular value of the power coefficient that power law researchers find depends on the nature of the movement pattern analyzed; different values of beta will be found for different patterns of movement. This is an artifact of estimating beta by regressing log® on log(V) and leaving out log(D).

So your claim is that when power-law researchers regress log® on log(V), the reason that beta varies from 1/3 is that they have failed to include log(D) as a predictor variable in the regression. However, by including log(D), taking the antilog brings you back to your formula for finding V from D and R:

V = D1/3R1/3

As I myself pointed out to you during my visit to Laputa (and the reviewers concur), the original equation for computing R from V and D takes account of the velocities and accelerations of the points along the curve in such a way that R and V can have practically any relationship.

To prove this fact, I have provided a table giving hypothetical observed values of V and R. I constructed this table so that V increases by a constant of 0.1 with each observation and R decreases by the same amount. I chose these specific values of V and R to produce a velocity that increases as the curve tightens (R becomes smaller).

Because D = V3/R, I was able to supply the values of D that must have been true of any point along the trajectory, so long as there is motion and R is not infinite (i.e., not a straight line).

I then computed V from R and D using your equation. The computed velocities, based on R and D, match the observed velocities, confirming that the equation is being solved properly.

V

R

D

R1/3

D1/3

V formula

5.0

10.0

12.5000

2.154435

2.320794

5.0

5.1

9.9

13.3991

2.147229

2.375154

5.1

5.2

9.8

14.3478

2.139975

2.429935

5.2

5.3

9.7

15.3481

2.132671

2.485146

5.3

5.4

9.6

16.4025

2.125317

2.540797

5.4

5.5

9.5

17.5132

2.117912

2.596898

5.5

5.6

9.4

18.6826

2.110454

2.653457

5.6

5.7

9.3

19.9132

2.102944

2.710486

5.7

5.8

9.2

21.2078

2.095379

2.767996

5.8

5.9

9.1

22.5691

2.087759

2.825996

5.9

6.0

9.0

24.0000

2.080084

2.884499

6.0

Below I have regressed V on R. Please note the linear (not power-law) relationship. It is not an artifact of the way either V or R are computed. It is an empirical relationship that could have been observed in the data.

image0076.png

You go on to claim that your model of movement control explains the power-law relationship between V and R. Here is your model:

image00166.png

Our reviewers note that your model specifies that the output of your control system affects V according to your equation solving V from D and R. However, you cannot know the value of R until you have found the values of V and D from the data and used them to compute R. In which case you already know what V is and do not have to compute it from D and R.

In addition, your model specifies that the control system(s) involved will produce trajectories via a set of time-varying reference values. If you are using a proportional controller with a leaky integrator output, the output trajectory can be nothing more than a low-pass filtered version of the time-varying reference signals. This does nothing to explain why one would expect a control system to produce changes in V and R that conform to the power law (if indeed they do).

We are sorry to have to inform you of this decision to reject your paper and wish you every success in the future.

Gulliver

Content-Type: image/png; name="image002.png"
Content-Disposition: inline; filename="image002.png"
Content-ID: <image002.png@01D1F585.B9D64D60>
X-Attachment-Id: db5c6200cf4ccef6_0.2

Content-Type: image/png; name="image003.png"
Content-Disposition: inline; filename="image003.png"
Content-ID: <image003.png@01D1F584.F8C40860>
X-Attachment-Id: db5c6200cf4ccef6_0.1

Content-Type: image/png; name="image001.png"
Content-Disposition: inline; filename="image001.png"
Content-ID: <image001.png@01D1F596.FB5646D0>
X-Attachment-Id: db5c6200cf4ccef6_0.4

Content-Type: image/png; name="image007.png"
Content-Disposition: attachment; filename="image007.png"
Content-ID: <image007.png@01D1F596.FB438220>
X-Attachment-Id: db5c6200cf4ccef6_0.3

image484.png

image00316.png

image00166.png

image0076.png

[Martin Taylor 2016.08.16.10.47]

[From Rick Marken (2016.08.13.1145)]

I guess trying to make things simple by going into a "kindergarten

level" of detail doesn’t work. So let’s see if the other extreme, no
detail at all, works.

No description of a shape property can have any dependence on time,

which means that velocity cannot enter into it. Curvature is such a
description. Velocity (dx/dt) is not relevant to curvature.

Does that help?

I could stop there, but I won't, against my better judgment.

Did you ask your math teacher son?

Actually, your mathematical derivation and mine are both correct.

They don’t formally contradict each other, and for any * specific
choice* of velocity profile, they don’t in practice.

The problem is that yours leaves a false dependence on velocity

separately in both the numerator and denominator of the expression
for curvature. It’s false, because in the curvature expression the
velocity is arbitrarily chosen; any positive velocity will do. In
the “square root sum of squares” expression, velocity is being
determined from measured values of derivatives. You can
choose to use this velocity in the curvature expression, and it
won’t affect the curvature computation. But then neither will the
curvature affect your choice of velocity to use.

When the expression for curvature is taken to be just that, a

description of a shape property, the dependencies on V cancel out
comletely, leaving a dimensionally correct expression that has in it
only items of dimension L (length) or 0 (number).

"V" in the curvature expression is only a formal parameter,

sometimes called an “intervening variable” introduced for
convenience. It doesn’t mean anything with respect to actual
velocities. As I have repeatedly pointed out, the “t” in the
derivatives of the curvature formula is just a map onto “s”,
distance along the curve. And that’s ALL it is, in contrast to its
use in the formula for velocity, where it means clock time. You have
to arbitrarily define velocity as some function of s, and by doing
so you define the map of t onto s. But as I pointed out several
times, so long as v is positive non-zero and differentiable
everywhere, it can be any function of s (or equivalently, of t) at
all.

Whatever the equation, if on one side of the equation you have a

variable “x” that cancels out of a fraction with x in numerator and
denominator, and rearrange variables so that the equation takes the
form “x = …” you have expressed a tautology, not an equation you
can use to determine the value of “x”. That’s a universal truth.

Because Alex's problem is why the velocities have a dependence on

the radius of curvature, not how well can a moving cursor follow the
movements of a reference signal. Yours is not a model of the power
law. It’s a model of a follower of changes in its reference
position, which, insofar as its control is good, automatically makes
it follow changes in reference speed.

I do like that concept. It's why your model is irrelevant to the

problem Alex posed initially. It’s why for so long I avoided
commenting on your model, since I assumed that the problem was
self-evident.

So far, so good. "It would be nice to" should be translated as "if

we want to address Alex’s question, we must".

How so, since the model just follows the reference as the reference

motion speeds up and slows down? Only if the reference speed obeys
the power law will the model output velocity that also follows the
power law. If it doesn’t, it’s a bad model of motion control, which
I doubt.

Test what about the model above? On the one hand you agree with

Bruce and me that the output velocity variation of your model is
that of the reference signal supplied from higher levels, and then
you contradict yourself by saying that you intend to test the model,
presumably as to its ability to self-generate the power-law
dependency regardless of variation in reference velocity. Since I
really don’t think you are an idiot, no matter how hard you have
been trying to demonstrate the contrary, there must be a resolution
of this contradiction that I am not seeing.

Exactly, exactly !!! How long have I been asking for this? Why did I

recently propose an experiment to try to tease apart one set of
possibilities from another?

I've no doubt it will. But having established that, we then have to

look for whatever controlled variable is responsible for the fact
that often the speed of the reference motion supplied to your model
of motion control follows the 1/3 power law – and for the fact that
there are defined conditions when it doesn’t.

You could have, if you would read either of my messages describing

the experiment and what it attempts to do. I think most of the
CSGnet readership probably does have a pretty good idea, though one
cannot tell with lurkers.

Martin

SpeedFormula.jpg

···

Martin Taylor (2016.08.13.12.25)

            <sup>MT: Actually, </sup>

RM: Correct. My X’s and Y’s should have dots over them.

                          RM: I don't understand why this is a

problem. Is there a new math rule that I
don’t know about? Power law researchers
use the following two equations to find
the instantaneous tangential velocity (V)
and instantaneous radial curvature (R) of
a movement pattern:

V = (X2+Y2 ) 1/2

                              </sup>

                            MT: Actually, your math teacher some missed a

beat here. The differentiation is by some parameter that
specifies a distance along the curve, and time doesn’t
do that unless you pre-specify V as a function of time.
The formula for curvature (1/R) is actually

          RM: Not Correct. The X and Y in the numerator of R

should have a dot over them, as they should in the
expression for V. They are the same derivative ; a
change in position over time, dt. So my derivation is
correct and your is not.

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V 2
(X2+Y2 ) – is
part of the numerator of R. So I think it
is perfectly correct (and my math teacher
son concurs) to write:

                            R

= [(V2)3/2]/|dXd2Y-d2XdY|

            MT: OK. What's wrong with that model is that

time, and therefore velocity, is not represented in the
model. Any velocity that appears on the output is
dependent on velocities of the reference in x and y.

RM: Why is that wrong?

                          RM: On that note maybe you could

explain what is wrong with my PCT model of
the power law as it is found in
intentionally produced curved movement.
Here it is again:

RM: What’s wrong with this model??

            MT: Hence the model

cannot be relevant to the question of why the velocity
is so often observed to vary as R1/3 , and
under other conditions does not.

          RM: So you don't like the idea that variations in input

(including variations in the velocity of these inputs) are
caused by variations in the reference for these inputs?
That’s actually the way PCT explains observed variations
in movement. What’s your model?

            MT: All your model

does is shove the question up a level so that we must
ask why the reference signal has those properties.

          RM: My model is a PCT explanation of movement control.

It has worked in other contexts and it works in this one.
The model assumes that the variations in the reference for
the position of the moved object (such as the pencil in
this case) are caused by higher level systems. And it
would be nice to study how and why higher order systems
vary these references.

          But the model, as it stands, is meant to account for

the observation of the power law in curved movement; and
the model does that (as I will demonstrate in my
experiments).

            MT: Indeed it would. How about starting by

suggesting another experiment, different from mine, to
narrow the search for the controlled variable(s)?

          RM: I am developing experiments that will test the

model above.

                          RM: It would sure by nice if we could

start talking about PCT explanations of
behavior again. Maybe you can get the ball
rolling, Erling!

            MT: First we need

to know what perception(s) that effective model might
control.

      RM: You first have to come up with a hypothesis about what the

controlled variable is in this situation.

I’ve already done (and published – s ee, for example,
Marken, R. S. (1991) Degrees of Freedom in Behavior. * Psychological
Science*, 2, 92 - 100) quite a lot of research
showing that the controlled variable in control of 2_D
movement is the X and Y position of the moved object (like a
cursor). So I’m rather confident that my model is controlling
the variable that people control when they make two dimension
movements. But this will be further confirmed, I’m sure, when
the model behaves exactly like the people in my experiments.

      RM: I would sure like to see your

alternative model. Without it I have no idea what the heck
you’re trying to test with your experiment. .

RM : So I’m rather confident that my model is controlling the variable that people control when they make two dimension movements. But this will be further confirmed, I’m sure, when the model behaves exactly like the people in my experiments

HB : So now it’s clear. You don’t beleive that PCT already modeled behavior exactly like the people in your experiments.You doubt about PCT.

I think that all your experiments and demos lean on wrong assumption that »behavior is control«. Including your articles. And this means that you don’t understand PCT and that you are doing your experiments which will prove that in YOUR MODEL !!! (which mostly bases on Bill’s model) will prove that »behavior is control«.

Bill proved a long time ago that people behave aproximately exactly as PCT predicts and they »Control perception«. But now you have some NEW MODEL !!! with new predictions how people exactly behave. Rick, why don’t you found your new behavioral theory (RCT) and found your own forum and show people how your theory is right. Why bugging CSGnet forum, where Bill already proved that »Perception is controlled«, wiht much stronger evidences than you can provide.

I’ll put some axioms of PCT which can be definitelly carried out of Bill’s work (and speccially from his diagram in LCS III) including also physiological evidences in B:CP :

  1.   Behavoir, output (movement or whatever) are not control, controlled…
    

<

  1.   There is no »controlled variable« in outer environment
    
  2.   There is no »Controled perceptual variable« (CPV) or Perceptually Controled variable (PCV) in input function and composite afferent nerv fibers
    
  3.   Control events don't happen at the same time in control loop but in succesion with time delay.
    

This can be the basic assumptions when dealing with whatever newness somebody wants to come out. But if somebody can prove that basic PCT axioms are not right please show your evidences. Speccialy physiological, because every »imagined construct« like Rick’s will have to be finally tested against physiological »facts«, because Bill gave these evidneces and I think they still hold even after so many years they were carried out. I think that main question Bill wanted to solve was not whether »Behavior is control« or »Perception is controlled« but how nervous system really work. And we are still quite some distance away from there. Others are more.

Bill P (Anniversary 2011) : Perceptual Control Theory (PCT) provides a general theory of functioning of organism.

Bill P (B:CP) : …too most readers the first part of this book will seem a direct denial of my hope, for it gives a delibrarelly mechanistic picture of how the nervous system behaves…. Only after the mechanistic model is thoroughly undersstaood will the reader see that it leads beyond ordinary mechanism and that it is capable of describing the interface between what we can represent as mechanism and what we cannot yet represent at all, but only in experience.

So Rick I think that first you will have to understand how organism and nervous system function with already known »facts«. I think that mish-mash with your »behavioral constructs« have to stop. I think that Powers ladies are on the move.

Best,

Boris

SpeedFormula.jpg

image0049.png

···

From: Richard Marken [mailto:rsmarken@gmail.com]
Sent: Saturday, August 13, 2016 8:46 PM
To: csgnet@lists.illinois.edu
Subject: Re: Looking at the Power Law through Laputasian Glasses

[From Rick Marken (2016.08.13.1145)]

Martin Taylor (2016.08.13.12.25)

RM: I don’t understand why this is a problem. Is there a new math rule that I don’t know about? Power law researchers use the following two equations to find the instantaneous tangential velocity (V) and instantaneous radial curvature (R) of a movement pattern:

V = (X2+Y2 )1/2

MT: Actually, cid:image001.jpg@01D1F621.78076800

RM: Correct. My X’s and Y’s should have dots over them.

RM: R = [(X2+Y2 )3/2]/|dXd2Y-d2XdY|

It turns out that V2 – (X2+Y2 ) – is part of the numerator of R. So I think it is perfectly correct (and my math teacher son concurs) to write:

R = [(V2)3/2]/|dXd2Y-d2XdY|

MT: Actually, your math teacher some missed a beat here. The differentiation is by some parameter that specifies a distance along the curve, and time doesn’t do that unless you pre-specify V as a function of time. The formula for curvature (1/R) is actually

RM: Not Correct. The X and Y in the numerator of R should have a dot over them, as they should in the expression for V. They are the same derivative; a change in position over time, dt. So my derivation is correct and your is not.

RM: On that note maybe you could explain what is wrong with my PCT model of the power law as it is found in intentionally produced curved movement. Here it is again:

Inline image 1

RM: What’s wrong with this model??

MT: OK. What’s wrong with that model is that time, and therefore velocity, is not represented in the model. Any velocity that appears on the output is dependent on velocities of the reference in x and y.

RM: Why is that wrong?

MT: Hence the model cannot be relevant to the question of why the velocity is so often observed to vary as R1/3, and under other conditions does not.

RM: So you don’t like the idea that variations in input (including variations in the velocity of these inputs) are caused by variations in the reference for these inputs? That’s actually the way PCT explains observed variations in movement. What’s your model?

MT: All your model does is shove the question up a level so that we must ask why the reference signal has those properties.

RM: My model is a PCT explanation of movement control. It has worked in other contexts and it works in this one. The model assumes that the variations in the reference for the position of the moved object (such as the pencil in this case) are caused by higher level systems. And it would be nice to study how and why higher order systems vary these references. But the model, as it stands, is meant to account for the observation of the power law in curved movement; and the model does that (as I will demonstrate in my experiments).

RM: It would sure by nice if we could start talking about PCT explanations of behavior again. Maybe you can get the ball rolling, Erling!

MT: Indeed it would. How about starting by suggesting another experiment, different from mine, to narrow the search for the controlled variable(s)?

RM: I am developing experiments that will test the model above.

MT: First we need to know what perception(s) that effective model might control.

RM: You first have to come up with a hypothesis about what the controlled variable is in this situation. I’ve already done (and published – see, for example, Marken, R. S. (1991) Degrees of Freedom in Behavior. Psychological Science, 2, 92 - 100) quite a lot of research showing that the controlled variable in control of 2_D movement is the X and Y position of the moved object (like a cursor). So I’m rather confident that my model is controlling the variable that people control when they make two dimension movements. But this will be further confirmed, I’m sure, when the model behaves exactly like the people in my experiments.

RM: I would sure like to see your alternative model. Without it I have no idea what the heck you’re trying to test with your experiment. .

Best

Rick

Richard S. Marken

“The childhood of the human race is far from over. We have a long way to go before most people will understand that what they do for others is just as important to their well-being as what they do for themselves.” – William T. Powers

[Martin Taylor 2016.08.18.11.14]

Here are a couple of comments on this thread, and repeats of a

couple of questions as yet unanswered.

[From Rick Marken (2016.08.13.1145)]

What did Rick omit after the word "actually"? This [Martin Taylor

2016.08.13.12.25]:

---------start MT quote-----
  ![curvatureFormulaByS.jpg|245x98](upload://4dWi0tOjX84Gux9EM2qYyNbfrXy.jpeg)



  Notice the "s" parameter, which is simply distance along the

curve. That’s the simplest parameter, but you could use any other
that uniquely specifies a location along the curve. Time doesn’t
come into the computation of curvature (or radius of curvature) at
all, because curvature isn’t a function of time.

  If you have prespecified some V, which is ds/dt, as a function of

either s or t, you can connect the two formulae, but you can’t do
it until after you specify V. Your specified V(t) can be anything,
provided it is never zero nor negative, and is continuous.
------end MT quote--------

And earlier, from  [Martin Taylor 2016.08.06.23.54]

-----begin MT quote ------
  Here's the basic equation, from which the

other is derived using the “V” mapping:

  ![curvatureFormulaByS.jpg|245x98](upload://4dWi0tOjX84Gux9EM2qYyNbfrXy.jpeg)



  How can these two formalae for curvature be the same? Remember

V=ds/dt, and that one can always replace dx/dz with dx/dqdq/dz.
So now we replace all the du/ds’s with du/ds
ds/dt = V*du/ds
(where “u” means any variable, such as x or y), and d2u/ds2
by V2*d2u/dt2.

  ![curvatureFormulaWithVs.jpg|296x98](upload://468awB4mAMKc6x1mhlqhjANfs0.jpeg)



  Since (V<sup>2</sup>)<sup>3/2</sup> = V<sup>3</sup>      , all the V's

vanish, leaving the original formula for curvature used by Rick. I
doesn’t matter what value of V you choose or how V changes along
the length of the curve, the curvature 1/R at that particular
point remains the same.
----------end MT quote-------

[MT now] So now I ask how Rick can possibly justify his: "RM: Not

Correct. The X and Y in the numerator of R should have a dot over
them, as they should in the expression for V. They are the * same
derivative* ; a change in position over time, dt. So my
derivation is correct and your is not."

My first re-asked question in response to the sentences just quoted:

“Did you ask your math teacher son?”

I probably should have asked why Rick used a form more commonly used

in theological disputes: “I’m right and you are wrong”. In those
disputes, there’s no independent arbiter, whereas in this case there
is. To prove one of us is wrong, all that is necessary is to
demonstrate a mathematical error. But, as I pointed out in the same
message, both derivations are formally correct. The problem in
Rick’s is his assertion that the time variable is necessarily the
same for the velocity calculation and the curvature calculation. As
I pointed out, they can be, but they need not be.
The dx and dy variables in the velocity calculation is determined by
measurement, whereas in the curvature calculation the velocity
variable is completely arbitrary, for the reason explained in the
two quotes from my earlier messages.

Which leads to my second re-asked question:

------MT quote-----
  No description of a shape property can have

any dependence on time, which means that velocity cannot enter
into it. Curvature is such a description. Velocity (dx/dt) is not
relevant to curvature.

  Does that help?

-----end MT quote------

Well, does it? If not, why not?

I'd appreciate clear answers to these questions, particularly the

one about whether you have asked a mathematically competent person
to check the accuracy of what I say, as I asked you to do in [Martin
Taylor 2016.08.13.12.25].

Martin

SpeedFormula.jpg

···

Martin Taylor (2016.08.13.12.25)

            <sup>MT: Actually, </sup>

RM: Correct. My X’s and Y’s should have dots over them.

                            MT: Actually, your math teacher some missed a

beat here. The differentiation is by some parameter that
specifies a distance along the curve, and time doesn’t
do that unless you pre-specify V as a function of time.
The formula for curvature (1/R) is actually

          RM: Not Correct. The X and Y in the numerator of R

should have a dot over them, as they should in the
expression for V. They are the same derivative ; a
change in position over time, dt. So my derivation is
correct and your is not.

                          RM: I don't understand why this is a

problem. Is there a new math rule that I
don’t know about? Power law researchers
use the following two equations to find
the instantaneous tangential velocity (V)
and instantaneous radial curvature (R) of
a movement pattern:

V = (X2+Y2 ) 1/2

                              </sup>

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V 2
(X2+Y2 ) – is
part of the numerator of R. So I think it
is perfectly correct (and my math teacher
son concurs) to write:

                            R

= [(V2)3/2]/|dXd2Y-d2XdY|

                          RM: On that note maybe you could

explain what is wrong with my PCT model of
the power law as it is found in
intentionally produced curved movement.

[From Rick Marken (2016.08.18.1320)]

SpeedFormula.jpg

curvatureFormulaWithVs.jpg

curvatureFormulaByS.jpg

curvatureFormulaByS.jpg

···

Martin Taylor (2016.08.18.11.14)–

MT: Here are a couple of comments on this thread, and repeats of a

couple of questions as yet unanswered.

RM: And they will remain unanswered because they are irrelevant. My spreadsheet model shows that a control model can account for the observed power law. You got a problem with that? Then show me how it doesn’t

Best

Rick

[From Rick Marken (2016.08.13.1145)]

What did Rick omit after the word "actually"? This [Martin Taylor

2016.08.13.12.25]:

---------start MT quote-----
  Notice the "s" parameter, which is simply distance along the

curve. That’s the simplest parameter, but you could use any other
that uniquely specifies a location along the curve. Time doesn’t
come into the computation of curvature (or radius of curvature) at
all, because curvature isn’t a function of time.

  If you have prespecified some V, which is ds/dt, as a function of

either s or t, you can connect the two formulae, but you can’t do
it until after you specify V. Your specified V(t) can be anything,
provided it is never zero nor negative, and is continuous.
------end MT quote--------

And earlier, from  [Martin Taylor 2016.08.06.23.54]

-----begin MT quote ------
  Here's the basic equation, from which the

other is derived using the “V” mapping:

  How can these two formalae for curvature be the same? Remember

V=ds/dt, and that one can always replace dx/dz with dx/dqdq/dz.
So now we replace all the du/ds’s with du/ds
ds/dt = V*du/ds
(where “u” means any variable, such as x or y), and d2u/ds2
by V2*d2u/dt2.

  Since (V<sup>2</sup>)<sup>3/2</sup> = V<sup>3</sup>      , all the V's

vanish, leaving the original formula for curvature used by Rick. I
doesn’t matter what value of V you choose or how V changes along
the length of the curve, the curvature 1/R at that particular
point remains the same.
----------end MT quote-------

[MT now] So now I ask how Rick can possibly justify his: "RM: Not

Correct. The X and Y in the numerator of R should have a dot over
them, as they should in the expression for V. They are the * same
derivative* ; a change in position over time, dt. So my
derivation is correct and your is not."

My first re-asked question in response to the sentences just quoted:

“Did you ask your math teacher son?”

I probably should have asked why Rick used a form more commonly used

in theological disputes: “I’m right and you are wrong”. In those
disputes, there’s no independent arbiter, whereas in this case there
is. To prove one of us is wrong, all that is necessary is to
demonstrate a mathematical error. But, as I pointed out in the same
message, both derivations are formally correct. The problem in
Rick’s is his assertion that the time variable is necessarily the
same for the velocity calculation and the curvature calculation. As
I pointed out, they can be, but they need not be.
The dx and dy variables in the velocity calculation is determined by
measurement, whereas in the curvature calculation the velocity
variable is completely arbitrary, for the reason explained in the
two quotes from my earlier messages.

  No description of a shape property can have

any dependence on time, which means that velocity cannot enter
into it. Curvature is such a description. Velocity (dx/dt) is not
relevant to curvature.

  Does that help?
Which leads to my second re-asked question:



------MT quote-----

-----end MT quote------



Well, does it? If not, why not?



I'd appreciate clear answers to these questions, particularly the

one about whether you have asked a mathematically competent person
to check the accuracy of what I say, as I asked you to do in [Martin
Taylor 2016.08.13.12.25].

Martin


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Martin Taylor (2016.08.13.12.25)

            <sup>MT: Actually, </sup>

RM: Correct. My X’s and Y’s should have dots over them.

                            MT: Actually, your math teacher some missed a

beat here. The differentiation is by some parameter that
specifies a distance along the curve, and time doesn’t
do that unless you pre-specify V as a function of time.
The formula for curvature (1/R) is actually

          RM: Not Correct. The X and Y in the numerator of R

should have a dot over them, as they should in the
expression for V. They are the same derivative ; a
change in position over time, dt. So my derivation is
correct and your is not.

                          RM: I don't understand why this is a

problem. Is there a new math rule that I
don’t know about? Power law researchers
use the following two equations to find
the instantaneous tangential velocity (V)
and instantaneous radial curvature (R) of
a movement pattern:

V = (X2+Y2 ) 1/2

                              </sup>

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V 2
(X2+Y2 ) – is
part of the numerator of R. So I think it
is perfectly correct (and my math teacher
son concurs) to write:

                            R

= [(V2)3/2]/|dXd2Y-d2XdY|

                          RM: On that note maybe you could

explain what is wrong with my PCT model of
the power law as it is found in
intentionally produced curved movement.

[Martin Taylor 2016.08.18.16.29]

[From Rick Marken (2016.08.18.1320)]

I have. Bruce has. We have repeatedly shown you how it doesn't and

why it doesn’t, and why it can’t, in outline and in detail. We have,
most recently, asked you to try your spreadsheet with a reference
motion that doesn’t force the output to follow the 1/3 power law,
and told you how that’s easy to do.

What I don't understand isn't your movement control model, because

that is extremely easy to understand, but why you don’t consider and
respond to the problems we have raised. Answering questions about
something is often a way toward improved understanding. You might
even find in this case that the specific questions are not
irrelevant. How about, for example, dealing with the problem
illustrated by Bruce’s “Rectangle Parable”?

What I further don't understand is how you can continue, for over a

month now, with your absurd claim that a simple movement tracker can
introduce to its output movement a property that is not in the
reference variation that it is supposed to track…

We have asked you to try out a reference movement that does not

conform to the 1/3 (or 2/3) power law, and have offered several easy
ways you could do this. If your control model could account for the
power law, it would do so regardless of the reference velocity
variation. But apparently you don’t want to make the test, just as
you don’t want to think about the mathematical reasons why your
claim is silly.

It's nothing to do with PCT. It's to do with making the appropriate

tests of a PCT model designed for an entirely different purpose, but
which you claim to perform a function that every analysis says it
will not do.

I have no problem with being wrong. That happens to everyone from

time to time. But if you continue to assert that your model accounts
for the data, but won’t subject it to any legitimate test that is
proposed, I DO have a problem with that. This is supposed to be a
scientific forum devoted to a serious theory called “Perceptual
Control Theory”, not a theological one in which miracles are
accepted phenomena, never to be questioned. Your continued appeal to
higher authority (yourself) and tautological tests in place of
legitimate test and analysis brings disrepute on the name of Bill
Powers, and I don’t like it.

Martin

SpeedFormula.jpg

curvatureFormulaByS.jpg

curvatureFormulaByS.jpg

curvatureFormulaWithVs.jpg

···

Martin Taylor (2016.08.18.11.14)–

            MT: Here are a couple of comments on this thread, and

repeats of a couple of questions as yet unanswered.

          RM: And they will remain unanswered because they are

irrelevant. My spreadsheet model shows that a control
model can account for the observed power law. You got a
problem with that? Then show me how it doesn’t

Best

Rick

[From Rick Marken (2016.08.13.1145)]

            What did Rick omit after the word "actually"? This

[Martin Taylor 2016.08.13.12.25]:

            ---------start MT quote-----
              Notice the "s" parameter, which is simply distance

along the curve. That’s the simplest parameter, but
you could use any other that uniquely specifies a
location along the curve. Time doesn’t come into the
computation of curvature (or radius of curvature) at
all, because curvature isn’t a function of time.

              If you have prespecified some V, which is ds/dt, as a

function of either s or t, you can connect the two
formulae, but you can’t do it until after you specify
V. Your specified V(t) can be anything, provided it is
never zero nor negative, and is continuous.
------end MT quote--------

            And earlier, from  [Martin Taylor 2016.08.06.23.54]

            -----begin MT quote ------
              Here's the basic equation, from

which the other is derived using the “V” mapping:

              How can these two formalae for curvature be the same?

Remember V=ds/dt, and that one can always replace
dx/dz with dx/dqdq/dz. So now we replace all the
du/ds’s with du/ds
ds/dt = V*du/ds (where “u” means
any variable, such as x or y), and d2u/ds2
by V2*d2u/dt2.

              Since (V<sup>2</sup>)<sup>3/2</sup> = V<sup>3</sup>                  ,

all the V’s vanish, leaving the original formula for
curvature used by Rick. I doesn’t matter what value of
V you choose or how V changes along the length of the
curve, the curvature 1/R at that particular point
remains the same.
----------end MT quote-------

            [MT now] So now I ask how Rick can possibly justify his:

“RM: Not Correct. The X and Y in the numerator of R
should have a dot over them, as they should in the
expression for V. They are the same derivative ;
a change in position over time, dt. So my derivation is
correct and your is not.”

            My first re-asked question in response to the sentences

just quoted: “Did you ask your math teacher son?”

            I probably should have asked why Rick used a form more

commonly used in theological disputes: “I’m right and
you are wrong”. In those disputes, there’s no
independent arbiter, whereas in this case there is. To
prove one of us is wrong, all that is necessary is to
demonstrate a mathematical error. But, as I pointed out
in the same message, both derivations are formally
correct. The problem in Rick’s is his assertion that the
time variable is necessarily the same for the velocity
calculation and the curvature calculation. As I pointed
out, they can be, but they need not be.
The dx and dy variables in the velocity calculation is
determined by measurement, whereas in the curvature
calculation the velocity variable is completely
arbitrary, for the reason explained in the two quotes
from my earlier messages.

                No description of a shape

property can have any dependence on time, which
means that velocity cannot enter into it. Curvature
is such a description. Velocity (dx/dt) is not
relevant to curvature.

                Does that help?
             Which leads to my second re-asked question:



            ------MT quote-----

-----end MT quote------

            Well, does it? If not, why not?



            I'd appreciate clear answers to these questions,

particularly the one about whether you have asked a
mathematically competent person to check the accuracy of
what I say, as I asked you to do in [Martin Taylor
2016.08.13.12.25].

                Martin


Richard S. Marken

                                    "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand that
what they do for
others is just as important to
their well-being as what they do
for
themselves." – William T.
Powers

Martin Taylor (2016.08.13.12.25)

                          <sup>MT: Actually,
                            </sup>
                        RM: Correct. My X's and Y's should have

dots over them.

                                                      MT: Actually, your math teacher

some missed a beat here. The
differentiation is by some parameter that
specifies a distance along the curve, and
time doesn’t do that unless you
pre-specify V as a function of time. The
formula for curvature (1/R) is actually

                        RM: Not Correct. The X and Y in the

numerator of R should have a dot over them,
as they should in the expression for V. They
are the same derivative ; a change in
position over time, dt. So my derivation is
correct and your is not.

                                        RM: I don't understand

why this is a problem. Is
there a new math rule that I
don’t know about? Power law
researchers use the
following two equations to
find the instantaneous
tangential velocity (V) and
instantaneous radial
curvature (R) of a movement
pattern:

V = (X2+Y2 ) 1/2

                                            </sup>

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V2 – (X2+Y2 )
is
part of the numerator of R.
So I think it is perfectly
correct (and my math teacher
son concurs) to write:

                                          R

= [(V2)3/2]/|dXd2Y-d2 XdY|

                                        RM: On that note maybe

you could explain what is
wrong with my PCT model of
the power law as it is found
in intentionally produced
curved movement.

[From Rick Marken (2016.08.18.1415)]

curvatureFormulaByS.jpg

SpeedFormula.jpg

curvatureFormulaWithVs.jpg

curvatureFormulaByS.jpg

···

Martin Taylor (2016.08.18.16.29)–

MT: I have. Bruce has. We have repeatedly shown you how it doesn't and

why it doesn’t, and why it can’t, in outline and in detail.

RM: You have not been very convincing.

MT: We have,

most recently, asked you to try your spreadsheet with a reference
motion that doesn’t force the output to follow the 1/3 power law,
and told you how that’s easy to do.

RM: The reference in my model is fixed at 0.

MT: What I don't understand isn't your movement control model, because

that is extremely easy to understand, but why you don’t consider and
respond to the problems we have raised.

RM: Because they are not problems, such as the ridiculous idea the reference motion could force the the output to follow the 1/3 power law. But I made the reference fixed anyway in my spreadsheet so that even that misconception couldn’t be used against the model.

RM: By the way, I would sure like to hear your counter explanation of the power law. It’s gets kind of tiresome just hearing that the PCT explanation is wrong (when it clearly works).

Best

Rick

Answering questions about

something is often a way toward improved understanding. You might
even find in this case that the specific questions are not
irrelevant. How about, for example, dealing with the problem
illustrated by Bruce’s “Rectangle Parable”?

What I further don't understand is how you can continue, for over a

month now, with your absurd claim that a simple movement tracker can
introduce to its output movement a property that is not in the
reference variation that it is supposed to track…

We have asked you to try out a reference movement that does not

conform to the 1/3 (or 2/3) power law, and have offered several easy
ways you could do this. If your control model could account for the
power law, it would do so regardless of the reference velocity
variation. But apparently you don’t want to make the test, just as
you don’t want to think about the mathematical reasons why your
claim is silly.

It's nothing to do with PCT. It's to do with making the appropriate

tests of a PCT model designed for an entirely different purpose, but
which you claim to perform a function that every analysis says it
will not do.

I have no problem with being wrong. That happens to everyone from

time to time. But if you continue to assert that your model accounts
for the data, but won’t subject it to any legitimate test that is
proposed, I DO have a problem with that. This is supposed to be a
scientific forum devoted to a serious theory called “Perceptual
Control Theory”, not a theological one in which miracles are
accepted phenomena, never to be questioned. Your continued appeal to
higher authority (yourself) and tautological tests in place of
legitimate test and analysis brings disrepute on the name of Bill
Powers, and I don’t like it.

Martin

          RM:My spreadsheet model shows that a control

model can account for the observed power law. You got a
problem with that? Then show me how it doesn’t

Best

Rick

[From Rick Marken (2016.08.13.1145)]

            What did Rick omit after the word "actually"? This

[Martin Taylor 2016.08.13.12.25]:

            ---------start MT quote-----
              Notice the "s" parameter, which is simply distance

along the curve. That’s the simplest parameter, but
you could use any other that uniquely specifies a
location along the curve. Time doesn’t come into the
computation of curvature (or radius of curvature) at
all, because curvature isn’t a function of time.

              If you have prespecified some V, which is ds/dt, as a

function of either s or t, you can connect the two
formulae, but you can’t do it until after you specify
V. Your specified V(t) can be anything, provided it is
never zero nor negative, and is continuous.
------end MT quote--------

            And earlier, from  [Martin Taylor 2016.08.06.23.54]

            -----begin MT quote ------
              Here's the basic equation, from

which the other is derived using the “V” mapping:

              How can these two formalae for curvature be the same?

Remember V=ds/dt, and that one can always replace
dx/dz with dx/dqdq/dz. So now we replace all the
du/ds’s with du/ds
ds/dt = V*du/ds (where “u” means
any variable, such as x or y), and d2u/ds2
by V2*d2u/dt2.

              Since (V<sup>2</sup>)<sup>3/2</sup> = V<sup>3</sup>                  ,

all the V’s vanish, leaving the original formula for
curvature used by Rick. I doesn’t matter what value of
V you choose or how V changes along the length of the
curve, the curvature 1/R at that particular point
remains the same.
----------end MT quote-------

            [MT now] So now I ask how Rick can possibly justify his:

“RM: Not Correct. The X and Y in the numerator of R
should have a dot over them, as they should in the
expression for V. They are the same derivative ;
a change in position over time, dt. So my derivation is
correct and your is not.”

            My first re-asked question in response to the sentences

just quoted: “Did you ask your math teacher son?”

            I probably should have asked why Rick used a form more

commonly used in theological disputes: “I’m right and
you are wrong”. In those disputes, there’s no
independent arbiter, whereas in this case there is. To
prove one of us is wrong, all that is necessary is to
demonstrate a mathematical error. But, as I pointed out
in the same message, both derivations are formally
correct. The problem in Rick’s is his assertion that the
time variable is necessarily the same for the velocity
calculation and the curvature calculation. As I pointed
out, they can be, but they need not be.
The dx and dy variables in the velocity calculation is
determined by measurement, whereas in the curvature
calculation the velocity variable is completely
arbitrary, for the reason explained in the two quotes
from my earlier messages.

                No description of a shape

property can have any dependence on time, which
means that velocity cannot enter into it. Curvature
is such a description. Velocity (dx/dt) is not
relevant to curvature.

                Does that help?
             Which leads to my second re-asked question:



            ------MT quote-----

-----end MT quote------

            Well, does it? If not, why not?



            I'd appreciate clear answers to these questions,

particularly the one about whether you have asked a
mathematically competent person to check the accuracy of
what I say, as I asked you to do in [Martin Taylor
2016.08.13.12.25].

                Martin


Richard S. Marken

                                    "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand that
what they do for
others is just as important to
their well-being as what they do
for
themselves." – William T.
Powers

Martin Taylor (2016.08.13.12.25)

                          <sup>MT: Actually,
                            </sup>
                        RM: Correct. My X's and Y's should have

dots over them.

                                                      MT: Actually, your math teacher

some missed a beat here. The
differentiation is by some parameter that
specifies a distance along the curve, and
time doesn’t do that unless you
pre-specify V as a function of time. The
formula for curvature (1/R) is actually

                        RM: Not Correct. The X and Y in the

numerator of R should have a dot over them,
as they should in the expression for V. They
are the same derivative ; a change in
position over time, dt. So my derivation is
correct and your is not.

                                        RM: I don't understand

why this is a problem. Is
there a new math rule that I
don’t know about? Power law
researchers use the
following two equations to
find the instantaneous
tangential velocity (V) and
instantaneous radial
curvature (R) of a movement
pattern:

V = (X2+Y2 ) 1/2

                                            </sup>

RM: R
= [(X2+Y2 )3/2]/|dXd2Y-d2 XdY|

It turns out that V2 – (X2+Y2 )
is
part of the numerator of R.
So I think it is perfectly
correct (and my math teacher
son concurs) to write:

                                          R

= [(V2)3/2]/|dXd2Y-d2 XdY|

                                        RM: On that note maybe

you could explain what is
wrong with my PCT model of
the power law as it is found
in intentionally produced
curved movement.

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Martin Taylor 2016.08.18.17.22]

[From Rick Marken (2016.08.18.1415)]

Then I don't understand it at all. I thought that

was your model, and that the squiggle was the reference movement

that the tracker followed. The functions and the form of the diagram
make it look very much as though the pencil is supposed to make the
same squiggle as what I thought was the reference track.

What are those two squiggles, then? They look very much alike, so

it’s not surprising I thought the upper one was a reference track
and the lower one the performance of the model when that was the
reference. And where in this figure is the reference value that is
zero? I don’t see any other candidate reference values, and nor do I
see anything labelled as “zero”.

Maybe you could explain the model more carefully than you have done

so far, making clear in particular what those squiggles are supposed
to represent, and where in the figure the real reference zero for
the x and y controllers is, because if I’ve been barking up the
wrong tree since you first presented this figure, I apologise.

Martin
···

Martin Taylor (2016.08.18.16.29)–

            MT: I have. Bruce has. We have repeatedly shown

you how it doesn’t and why it doesn’t, and why it can’t,
in outline and in detail.

RM: You have not been very convincing.

            MT: We have, most

recently, asked you to try your spreadsheet with a
reference motion that doesn’t force the output to follow
the 1/3 power law, and told you how that’s easy to do.

RM: The reference in my model is fixed at 0.

                        RM:My spreadsheet model shows that a

control model can account for the observed
power law. You got a problem with that? Then
show me how it doesn’t

[From Bruce Abbott (2016.08.18.1855 EDT)]

Rick Marken (2016.08.18.1320) –

Martin Taylor (2016.08.18.11.14)Â

MT: Here are a couple of comments on this thread, and repeats of a couple of questions as yet unanswered.

RM: And they will remain unanswered because they are irrelevant. My spreadsheet model shows that a control model can account for the observed power law. You got a problem with that? Then show me how it doesn’t.

BA: Alex, Martin, and I have already done that – in spades! Rather than dealing with the devastating criticisms we have levied against your assertion, you have chosen to ignore them, refusing, as I said, to “look through the telescope.â€?

BA: It is now up to you to provide a convincing argument or arguments why our mathematical and empirical demonstrations are wrong. These show unequivocally (a) that your analysis of the power law based on including log D in the regression can only give you back the equation for computing the radius of curvature, (b) that tangential velocity V and radius R can vary independently in nature, even though V is used in the computation of R (as R. Kennaway demonstrated so nicely), (c) the V used to compute R is not necessarily a change in position with respect to time, in fact time has nothing to do with what is a mathematical relationship used to compute R, (d) using reference variations based on constant increments of theta to compute sines and cosines is guaranteed to produce a relationship between tangential velocity and position along the ellipse (or other figures so generated so long as R and V vary) that conforms to the power law, and (e) filtering these reference variations through control systems for x and y position does nothing but reproduce (in somewhat degraded form) the relationships between V and R that are built into the reference variations.

BA: You assert that these mathematical considerations are “irrelevant.� We have shown that they are extremely relevant. You have yet to mount an argument of any sort to prove that they are not relevant, and saying it’s so doesn’t make it so.

Bruce

[From Rick Marken (2016.08.19.0935)]

···

Martin Taylor (2016.08.18.17.22)–

MT: Then I don’t understand it at all. I thought that

was your model, and that the squiggle was the reference movement

that the tracker followed.

RM: That is the PCT model of arbitrary movement of the squiggle. Since you and Bruce criticized the PCT model by asserting that the power law was inherent in the reference movement (which it is) I had the model control the difference between cursor and target at a fixed reference of zero in a pursuit tracking task in order to show that it’s the shape of the movement that matters, whether it’s determined by variations in the reference signal or not.

MT: The functions and the form of the diagram

make it look very much as though the pencil is supposed to make the
same squiggle as what I thought was the reference track.

RM: Yes, the pencil (or, in the case of the spreadsheet, the cursor) movements follow the reference movements; that’s how control systems work. But as my spreadsheet demo shows, the outputs (mouse movements) that produce the observed pattern of (cursor) movement (whatever it is) are nothing like that pattern, whether the control system is controlling input relative to a fixed or variable reference. So in either case, the outputs of a control system have nothing to do with the observed relationship between the instantaneous velocity and curvature of the pencil (or cursor) movements that are a consequence of these outputs.

MT: What are those two squiggles, then?

RM: They are one possible way that a controller can autonomously vary the references for the X and Y position of the pencil (or cursor) over time.

MT: They look very much alike, so

it’s not surprising I thought the upper one was a reference track
and the lower one the performance of the model when that was the
reference.

RM: Your thought was correct. The upper one is a reference track and the lower one is the resulting actual track, which is a nearly exact copy of the reference track. This is because, per PCT, the variance in the controlled variable is almost exactly equal to the variance in the reference for that variable: q.i ~ r.

MT: And where in this figure is the reference value that is

zero? I don’t see any other candidate reference values, and nor do I
see anything labelled as “zero”.

RM: The reference value is fixed at zero in the spreadsheet version of the model; the model is controlling for a fixed distance of zero between cursor and moving target.

MT: Maybe you could explain the model more carefully than you have done

so far, making clear in particular what those squiggles are supposed
to represent, and where in the figure the real reference zero for
the x and y controllers is, because if I’ve been barking up the
wrong tree since you first presented this figure, I apologise.

RM: You’ve been barking up the wrong tree (the output generation tree) but not because of anything having to do with whether references vary or not. You’ve been barking up the wrong tree because you seem to think that control systems calculate outputs; in fact, they control inputs. The PCT model and tracking task that are implemented in the spreadsheet show that the power law is simply a measure of the relationship between measures of curvature and velocity

RM: By the way, before we go on I would really like to know what you think the power law shows regarding movement control. Why do you think the power law is observed?

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

RM: The reference in my model is fixed at 0.

[From Rick Marken (2016.08.19.1010)]

···

Bruce Abbott (2016.08.18.1855 EDT)

Â

RM: …My spreadsheet model shows that a control model can account for the observed power law. You got a problem with that? Then show me how it doesn’t.

Â

BA: Alex, Martin, and I have already done that – inn spades!Â

RM: I guess I didn’t catch it.Â

Â

BA: It is now up to you to provide a convincing argument or arguments why our mathematical and empirical demonstrations are wrong.Â

RM: Your mathematical and  empirical demonstrations are not so much wrong as irrelevant. What we’ve got is data that show an approximately 1/3 power relationship between R and V for certain human movements – such as elliptical movements –  and a 2/3 power relationship between C and A for fly larva movement. Those are the facts to be explained. My PCT model explains these facts. It produces approximately a 1/3 power law between R and V when it traces out an ellipse (as demonstrated by the tracking task in the spreadsheet demo); and it produces a 2/3 power law when it makes a squiggle movement (which is demonstrated by the “squiggle” button of the spreadsheet). If you think this model is wrong, the correct way to show that is to present data that the model can’t account for. Got data?

 BA: You assert that these mathematical considerations are “irrelevant.â€? We have shown that they are extremely relevant.

RM: No you haven’t. They are not relevant because they don’t speak to the facts that we are trying to understand. The facts we are trying to understand are the power relationships that are (or sometimes are not) observed between curvature and velocity in various movements. The PCT model produces movements that result in the 1/3 (and 2/3) power relationships that have been observed in the articles on the power law that I’ve been sent (and can be observed by doing the tracking task in the spreadsheet).Â

RM: The tracking task also shows that the movements of the outputs that keep the cursor moving in an elliptical pattern do not follow a power law at all. The model currently doesn’t capture that fact (the outputs of the model do follow the power law). This is actually something useful that comes from looking at the data in terms of power law analysis; it shows that a one level PCT model doesn’t account for all aspects of the tracking behavior. I’ll be working on developing a two level model that, hopefully, will account for both the 1/3 power law seen with elliptical movement (which the model already handles) and the non-power law seen in the movements of the outputs that produces this elliptical result.

BA: You have yet to mount an argument of any sort to prove that they are not relevant, and saying it’s so doesn’t make it so.

RM: I hope what I said above helps you understand why the math is irrelevant. But whether it does or not, I would like you to tell me what I asked of Martin as well: Â What do you think the power law shows regarding movement control? Why do you think the power law is observed? What, in other words, is your alternative to my PCT account of the power law?

Best

Rick


Richard S. MarkenÂ

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Martin Taylor 2016.08.19.14.00]

[From Rick Marken (2016.08.19.0935)]

But where is the velocity? It's the along-track velocity of the

reference squiggle that is critical, not its shape.

PCT pre-101.

That's what I thought all along. It's presumably a nearly exact copy

of the reference track’s velocity, too, depending on the transport
lag and integration rate parameters.

OK. That's not evident in the diagram.

PCT pre-101.

But I ask for the Nth time, where is the along-track speed variation

in the reference trace in your spreadsheet? In the one you
distributed, you use a reference track that, by its construction
from x and y variations that are composed of sine-waves over time,
imposes a 1/3 power law on the cursor velocity. Bruce says that even
the disturbances are made the same way, so that the output of any
decent control system must conform to the same power law. It’s
forced by the construction, and is not a property of the movement
control system.

To test the model you MUST use a reference track in which the

along-track velocity is independent of the local curvature. It’s
easy to do. Here’s anothe method to add to the ones suggested
previously. You could have a “squiggle-like” column listing some
arbitrarily varying local velocity in x and in y, and integrate that
to produce the reference squiggle. If the cursor speed conforms to
the 1/3 power law when the reference speed does not, then you would
really have a significant advance in answering Alex’s question.

Alex asked that question way, way, back when. Since then the CSGnet

discussion has been all about how a trivial motion tracking control
system actually produces the shapes it has been supposed to track.
The question of why people and other organisms often produce a
consistent relation between along-track speed and local curvature
has been lost in the fog.

Does the power law show anything regarding movement control? I don't

know. That’s why I proposed an experiment that might distinguish
whether the answer lies in what is perceived of the curve or in some
aspect of the motion control, and I certainly can’t start to answer
Alex’s question (or your different one) until at least that point is
resolved.

Anyway, the question has always about speed, not about shape. Your

“velocity”, as you have been told a zillion times, is simply a
formal parameter used in describing shape, that gets cancelled out
in the final description. It still has nothing whatever to do with
the observed velocity variation that led to Alex’s question.

Martin

···

Martin Taylor (2016.08.18.17.22)–

                            MT: Then I don't understand it at all. I thought

that

            was your model, and that the squiggle was the reference

movement that the tracker followed.

          RM: That is the PCT model of arbitrary movement of the

squiggle. Since you and Bruce criticized the PCT model by
asserting that the power law was inherent in the reference
movement (which it is) I had the model control the
difference between cursor and target at a fixed reference
of zero in a pursuit tracking task in order to show that
it’s the shape of the movement that matters, whether it’s
determined by variations in the reference signal or not.

                        RM: The reference in my model is fixed at
            MT: The functions

and the form of the diagram make it look very much as
though the pencil is supposed to make the same squiggle
as what I thought was the reference track.

          RM: Yes, the pencil (or, in the case of the

spreadsheet, the cursor) movements follow the reference
movements; that’s how control systems work. But as my
spreadsheet demo shows, the outputs (mouse movements) that
produce the observed pattern of (cursor) movement
(whatever it is) are nothing like that pattern, whether
the control system is controlling input relative to a
fixed or variable reference.

          So in either case, the outputs of a control system

have nothing to do with the observed relationship between
the instantaneous velocity and curvature of the pencil (or
cursor) movements that are a consequence of these outputs.

            MT: What are those

two squiggles, then?

          RM: They are one possible way that a controller can

autonomously vary the references for the X and Y position
of the pencil (or cursor) over time.

            MT: They look very

much alike, so it’s not surprising I thought the upper
one was a reference track and the lower one the
performance of the model when that was the reference.

          RM: Your thought was correct.  The upper one is a

reference track and the lower one is the resulting actual
track, which is a nearly exact copy of the reference
track.

          This is because, per PCT, the variance in the

controlled variable is almost exactly equal to the
variance in the reference for that variable: q.i ~ r.

            MT: And where in

this figure is the reference value that is zero? I don’t
see any other candidate reference values, and nor do I
see anything labelled as “zero”.

          RM: The reference value is fixed at zero in the

spreadsheet version of the model; the model is controlling
for a fixed distance of zero between cursor and moving
target.

            MT: Maybe you could

explain the model more carefully than you have done so
far, making clear in particular what those squiggles are
supposed to represent, and where in the figure the real
reference zero for the x and y controllers is, because
if I’ve been barking up the wrong tree since you first
presented this figure, I apologise.

          RM: You've been barking up the wrong tree (the output

generation tree) but not because of anything having to do
with whether references vary or not. You’ve been barking
up the wrong tree because you seem to think that control
systems calculate outputs; in fact, they control inputs.

          The PCT model and tracking task that are implemented

in the spreadsheet show that the power law is simply a
measure of the relationship between measures of curvature
and velocity

          RM: By the way, before we go on I would really like to

know what you think the power law shows regarding movement
control. Why do you think the power law is observed?

Best

Rick


Richard S. Marken

                                    "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand that
what they do for
others is just as important to
their well-being as what they do
for
themselves." – William T.
Powers

[From Rick Marken(2016.08.19.2100)]

image305.png

image306.png

···

Martin Taylor 2016.08.19.14.00)–

MT: But where is the velocity? It's the along-track velocity of the

reference squiggle that is critical, not its shape.

RM: You say it’s “critical”. Yet the model accounts for the data without it. So as the electrified Dylan said to the fan who yelled “Judas”, “I don’t believe you”.

MT: But I ask for the Nth time, where is the along-track speed variation

in the reference trace in your spreadsheet?

RM: Where is it in your model? As I said, there is no need to put an along-track speed variation in the reference trace into the PCT model in order to account for the data (power law). The reference trace is actually a trajectory – variation over time – not just a shape, by the way. So a regular old PCT model with fixed or variable reference accounts for all of the power law data with which I am familiar.

MT: In the one you

distributed, you use a reference track that, by its construction
from x and y variations that are composed of sine-waves over time,
imposes a 1/3 power law on the cursor velocity.

RM: This implies that you accept my explanation of the power law. An elliptical reference (target) track “imposes” a 1/3 power law only if my derivation of the relationship between V and R is correct:

V = D^(1/3) * R^(1/3)

RM:The 1/3 power law is “imposed” by an elliptical track because D is nearly constant for the type of ellipse used as the target trajectory in my spreadsheet demo.

RM: Your statement is also consistent with my explanation of the power law because it implies that the power coefficient that is observed in power law studies depends on the movement pattern (trajectory) produced. And, indeed, it does, as can be seen by pressing the “Scribble” button over and over (which should work on your Mac; just the “Data collection” macro doesn’t work on the Mac) and seeing the different estimates of beta for the different scribbles in the upper right corner. Just now I got estimates of beta for the different scribbles that ranged from .25 to .38. The average for 10 trials was .31.

MT: Bruce says that even

the disturbances are made the same way, so that the output of any
decent control system must conform to the same power law. It’s
forced by the construction, and is not a property of the movement
control system.

RM: It looks to me like you are complaining about the fact that the model accounts for the data. But maybe you are saying that somehow the fit to the data is forced by my choice of disturbances. Perhaps, like Bruce, you think the use of sine wave disturbances has something to do with it. So I’d be happy to use different disturbances; let me know what you would like me to use. But remember Fourier’s theorem; every disturbance waveform can be represented as the sum of sine waves of different phases and frequencies.

MT: To test the model you MUST use a reference track in which the

along-track velocity is independent of the local curvature.

RM: No, to test the model you must compare the model’s behavior to the behavior of the systems whose behavior you are trying to understand. If the model doesn’t fit the behavior, perhaps it’s because you haven’t done what you say (used a reference track in which the along-track velocity is independent of the local curvature). But my model does fit the data so your emphatic “MUST” is simply not true.

MT: It's

easy to do. Here’s anothe method to add to the ones suggested
previously. You could have a “squiggle-like” column listing some
arbitrarily varying local velocity in x and in y, and integrate that
to produce the reference squiggle. If the cursor speed conforms to
the 1/3 power law when the reference speed does not, then you would
really have a significant advance in answering Alex’s question.

RM: This is not the way I test models. I test models against actual observations, not against what someone says should be but hasn’t yet been observed. I have never seen any behavioral data in the power law literature that shows “cursor speed conforming to a 1/3 power when the reference speed does not” (whatever that means).

MT: Alex asked that question way, way, back when. Since then the CSGnet

discussion has been all about how a trivial motion tracking control
system actually produces the shapes it has been supposed to track.

RM: No, my part of the discussion answered Alex’s question by saying that the power law tells us nothing about movement control. The power law is simply a function of the type of movement trajectory produced and has nothing to do with how that trajectory was produced. That’s why even a “trivial motion tracking” control system can account for the results of power law experiments.

MT: Does the power law show anything regarding movement control? I don't

know.

RM: So if one possibility is that the power law doesn’t show anything about movement control why are you fighting so hard against my conclusion that, indeed, it doesn’t? You must think it actually does. What do you think it shows?

MT: That's why I proposed an experiment that might distinguish

whether the answer lies in what is perceived of the curve or in some
aspect of the motion control, and I certainly can’t start to answer
Alex’s question (or your different one) until at least that point is
resolved.

RM: The problem here is that the basis of the experiment is to vague. What does it mean to do an experiment to test whether the power law “has to do” with “what is perceived of the curve or in some aspect of the motion control”. What does the experiment predict will happen if the power law has to do with what is perceived of the curve? Why is that predicted? What does the experiment predict will happen if the power law has to do with some aspect of the motion control? Why is that predicted? My spreadsheet experiment is based on a very clearly defined model and it makes a very clear prediction: that the 1/3 and 2/3 power laws be found for certain movement trajectories – such as elliptical movement – regardless of how that movement is produced. And, indeed, when a person produces this movement trajectory:

RM: The trajectory results in a V vs R power law with coefficient .32. And this trajectory is produced by movements that look like this:

RM: Movements that, though somewhat elliptical, are quite different than the resulting input ellipse and have a beta coefficient of .13. I could make the outputs even more different than the resulting input by using wider band disturbances.

MT: Anyway, the question has always about speed, not about shape. Your

“velocity”, as you have been told a zillion times, is simply a
formal parameter used in describing shape, that gets cancelled out
in the final description. It still has nothing whatever to do with
the observed velocity variation that led to Alex’s question.

RM: That is completely false. The velocity I measure in the spreadsheet (as V or A) is the same velocity that is measured in power law studies. And you have not answered my question – what do you think the power law shows about movement control? I think you are avoiding an answer because the answer would betray your S-R approach to understanding behavior.

RM: The power law (as I said in the very first post on this topic) is an S-R concept; the relationship between curvature and velocity is seen as an S-R relationship, gussied up some fancy words like “constraint”. The power law is basically:

velocity = k * curvature^ (1/3 or 2/3)

The curvature of the movement is thought of as “constraining” the velocity of the movement through that curve. I think you and Bruce (and others) are very opposed to my PCT interpretation of the power law because it shows the S-R view of movement production - which you guys try to disguise using the jargon of PCT – is wrong. So prove me wrong and tell me the “correct” PCT explanation of the power law – since you are so emphatic about my PCT model of the power law being wrong.

RM: In the mean time, my earlier mention of Dylan reminded me of these lyrics, which seem appropriate to your point of view on the power law:

Your old road is rapidly agin’

Please get out of the new one

If you can’t lend a hand

Cause the times they are a’changin’

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

RM: That is the PCT model of arbitrary movement…

          RM: By the way, before we go on I would really like to

know what you think the power law shows regarding movement
control. Why do you think the power law is observed?

[Martin Taylor 2016.08.16.13.13]

[From Rick Marken(2016.08.19.2100)]

I suppose that if you ignore the relevant mathematics and say it's

irrelevant when it is presented to you in outline and also when it
is given in excruciating detail, I suppose you could say that. You
shouldn’t, but there you go. Nothing anyone but you can do anything
about it.

For the few who still might be interested, here's both overview and

detail approaches rolled into one.

Point 1. No description of shape can depend on anything but measures

of space. Time and velocity cannot enter into them.

----- detail follows----

There is a mathematical description of curvature in a Euclidean (x

vs. y) space. Curvature is defined as 1/R, where R is a radius of
curvature (the radius of an “osculating circle”, the circle
equivalent of a tangent straight line).

In the following formulae, "s" means distance along the curve, and

(x, y) is a location in the space. the differential ds in terms of x
and y is given by ds = (dx2 + dy2)1/2 from
basic Euclidean geometry. One can do as is done in the Wikipedia
article on Curvature, divide through this equation by ds and define
an “intermediate variable” or “formal variable” which I will call
“w”. The definition of “w” is

![spaceVelocityFormula.jpg|227x47](upload://6wzRiXObihJUCWY17TCM3z60XNF.jpeg)

The basic expression for curvature (it's based on computing the

tangent vector acceleration, which we don’t need to go into. If you
re interested, you could look up the actual derivation) is

![curvatureFormulaByS.jpg|245x98](upload://4dWi0tOjX84Gux9EM2qYyNbfrXy.jpeg)

so we can write

 ---- end detail----

![curvatureFormulaBySwithW.jpg|274x74](upload://qA0NXjXzDJhHwOMBlBHsI0JfsJM.jpeg)

If we do as Rick does, call the numerator of this fraction "D" and

transpose, we get

w<sup>3</sup> = D*R

or

w = D<sup>1/3</sup>*R<sup>1/3</sup>

Notice that nothing at all in this derivation has any relationship

to time or velocity. Those should not and do not enter into any
formula that is purely about the shape of a curve. And yet we arrive
at a formula for “w” that Rick calls a velocity. Not only that, but
Rick claims “w” to be the velocity that the “power law researchers”
measure in their experiments.

Point 2. Right at the start of this curious set of exchanges, we

pointed out to Rick that he had made a very excusable mistake,
figuring that correcting the mistake would end that particular
discussion, but we were sadly mistaken. The reason that the mistake
is easy to make is that the derivatives in the formula have been
represented in the “dotty” Newtonian notation, and are often taken
to be derivatives with respect to time.

----detail follows----

The problem with this is that the formulae do work if you use time

derivatives, but they do so if and only if you prespecify a velocity
profile along the track of the curve. You can set V as a function of
t (time) or of s (distance along the curve), because they convert
into each other, but you have to set it before you do any other
manipulations. It can be anything, provided that it defines a
one-to-one mapping between t and s.

 V(t)<sub>t= t0</sub> = (ds/dt)<sub>t=t0

</sub>or<sub>

</sub>V(s)<sub>s=s0</sub> = (ds/dt)<sub>s=s0</sub>

If you integrate V(t) after time t0 or V(s) after point s0, you get

a mapping of t onto s. For each moment in time there is a
corresponding point along the curve. Those values depends on the
arbitrarily defined V function of t or s, So let’s see (once again)
what we arrive at when we use this arbitrary mapping of t onto s,
starting with the formulae when you take the dot notation as
signifying differentiation with respect to time.

The first formula, which defined our intervening variable "w" now is

![SpeedFormulaWithV.jpg|234x50](upload://nVxWZ2LlIEzcRXlxGYQCpCcPOSn.jpeg)

The curvature formula becomes

![curvatureFormulaLeibnitz.jpg|245x98](upload://miDgbNUrNeBHkHCd47n5FGE61ev.jpeg)

It is perhaps worth noticing at this point that it would be formally

correct to multiply top and bottom by (dt)3 to avoid
having time mentioned in a formula for a description of space, but
we won’t do that because we want to see whether the formula as
written is correct on the assumption that we have specified a
velocity function of either time or distance along the curve. What
we will do is note that in calculus generally, dx/dy = dx/dzdz/dy
and d2x/dy2 = d2x/dz
(dz/dy)2 ,
and use these equalities to show that the equation is correct by
deriving it from the second equation above, the basic formula for
curvature, repeated here.

<img alt="" src="cid:part2.EA82C6B3.58EF46B9@mmtaylor.net" height="98" width="245">

Using the equivalences just mentioned, we can write this as

![curvatureFormulaBySandT.jpg|391x98](upload://xjyG6ZI8JEiWWRkrmdIZxMdrfod.jpeg)

And cancelling out the ds's we get the formula above

<img alt="" src="cid:part5.534D9446.66DB2731@mmtaylor.net" height="98" width="245">

Q.E.D.

Provided we have chosen some arbitrary velocity in advance as a

function of time or space, so that ds/dt has a value, the equation
for curvature with the time derivatives is correct.

----end detail---

It is very easy to ignore the requirement to specify an arbitrary

V(t) or V(s) and think that the two equations, one for the velocity
and one for the curvature, are independent. That’s exactly what Rick
did when he noticed that the denominator of this formula is actually
V3 . He thought that he could then do as we did above for
the formal variable “w”, which has no relation to velocity. So we
follow Rick and do it here, for V, but now we do it knowing that we
pre-set V. Rick calls the numerator of the fraction “D”, so the
equation becomes

1/R = D/V<sup>3</sup>

which immediately gives Rick's favourite equation for determining(!)

the already arbitrarily specified V.

V = D<sup>1/3</sup>*R<sup>1/3</sup>

Notice here that V is the same as the "w" variable we found earlier,

except that the equations were based on time derivatives instead of
distance derivatives. They are incorporated in the “D” variable.

The equation is true, but we can't use it to determine V because in

order to create the equation we had to create the arbitrary V
function before we started. The equation tautologically has V on
both sides, as the proof of correctness of the time-based formula
demonstrates. Alex pointed this out as soon as Rick introduced this
so-called equation, this tautology, but to no avail.

In other words, none of it, since you continue to claim that the

arbitrarily preset variable “V” in the equation above is what people
measure. They don’t. They measure how fast people and other
organisms move along a curving track. Quite a different thing.

      Not in the slightest. It

says that your so-called test is a cheat because it uses reference
trajectories whose speed along the curve is defined by the power
law. When you use real data, as you seem to do below, you get what
Alex and many other have found. And what Alex would like to have
explained.

      No, there's no implied

relationship between the shape and the speed. There may well be a
relationship in practice, as Alex said when he asked the original
question. His question was why this relation is found in practice
when there is no analytically determined reason for it. One can,
in principle, choose to go fast around the sharp curves and go
slow when there is a flat section. Apparently people don’t usually
do that, and I assume that your data contribute to the mass of
evidence that this is so.

      That's good. Without

knowing what you actually calculate, I can’t judge whether these
betas are what is usually computed, but I’ll take your word that
they are. I wonder whether your apparatus had some equivalent of
viscosity?

The problem is that your sine waves are sine waves with as a

function of time. The squiggle shapes have no connection with time,
so your comment (and your spreadsheet and your analysis) fails to
make the connection. You don’t need different disturbances, you need
different disturbance velocities . As I have suggested
several times, there are several easy ways to do this without
changing the shapes of either the target squiggle or the
disturbances. You shouldn’t need any new instructions how to do it.

Well, you are saying the same thing in different words. Yes you

must, and no you don’t, or haven’t yet.

You have not, so far as I know, ever demonstrated that your model

produces the power law when the along-track velocity of the target
squiggle does not.

I agree that's what you *should* do. I keep asking you do do

it. I don’t mind if you refuse to do it. I do mind that you keep
claiming that you have done it. It confuses the readership, and I’d
prefer that the CSGnet readership were treated to honest PCT
discussions rather than ones that depend on a mathematical
misunderstanding, however easy that misunderstanding is to make.

Martin
···

Martin Taylor 2016.08.19.14.00)–

            MT: But where is the velocity? It's the

along-track velocity of the reference squiggle that is
critical, not its shape.

          RM: You say it's "critical". Yet the model accounts for

the data without it.

          So as the electrified Dylan said to the fan who yelled

“Judas”, “I don’t believe you”.

            MT: But I ask for

the Nth time, where is the along-track speed variation
in the reference trace in your spreadsheet?

RM: Where is it in your model? As I said, there
is no need to put an along-track speed variation in the
reference trace into the PCT model in order to account for
the data (power law). The reference trace is actually a
trajectory – variation over time – not just a shape, by
the way. So a regular old PCT model with fixed or variable
reference accounts for all of the power law data with
which I am familiar.

            MT: In the one you

distributed, you use a reference track that, by its
construction from x and y variations that are composed
of sine-waves over time, imposes a 1/3 power law on the
cursor velocity.

            RM:  This

implies that you accept my explanation of the power law.

                RM: Your

statement is also consistent with my explanation of
the power law because it implies that the power
coefficient that is observed in power law studies
depends on the movement pattern (trajectory)
produced.

                And, indeed, it

does, as can be seen by pressing the “Scribble”
button over and over (which should work on your Mac;
just the “Data collection” macro doesn’t work on the
Mac) and seeing the different estimates of beta for
the different scribbles in the upper right corner.
Just now I got estimates of beta for the different
scribbles that ranged from .25 to .38. The average
for 10 trials was .31.

            MT: Bruce says that

even the disturbances are made the same way, so that the
output of any decent control system must conform to the
same power law. It’s forced by the construction, and is
not a property of the movement control system.

          RM: It looks to me like you are complaining about the

fact that the model accounts for the data. But maybe you
are saying that somehow the fit to the data is forced by
my choice of disturbances. Perhaps, like Bruce, you think
the use of sine wave disturbances has something to do with
it. So I’d be happy to use different disturbances; let me
know what you would like me to use. But remember Fourier’s
theorem; every disturbance waveform can be represented as
the sum of sine waves of different phases and frequencies.

            MT: To test the

model you MUST use a reference track in which the
along-track velocity is independent of the local
curvature.

          RM: No, to test the model you must compare the model's

behavior to the behavior of the systems whose behavior you
are trying to understand.

          If the model doesn't fit the behavior, perhaps it's

because you haven’t done what you say (used a reference
track in which the along-track velocity is independent of
the local curvature). But my model does fit the data so
your emphatic “MUST” is simply not true.

            MT: It's easy to do.

Here’s anothe method to add to the ones suggested
previously. You could have a “squiggle-like” column
listing some arbitrarily varying local velocity in x and
in y, and integrate that to produce the reference
squiggle. If the cursor speed conforms to the 1/3 power
law when the reference speed does not, then you would
really have a significant advance in answering Alex’s
question.

          RM: This is not the way I test models. I test models

against actual observations, not against what someone says
should be but hasn’t yet been observed.