Math Mistakes

image322.png

···

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

MT: In my view, Rick is a great experimenter and producer of lovely

demos of PCT, but he is no mathematician and no theorist.

To allow

his idiosyncratic private theories of mathematical relationships to
stand as though they were acceptable would be simply irresponsible.

RM: OK, let’s try this again slowly so you can show me where my mistake is. Let’s start by making sure that I’m using the right equations. Here are the two equations from Gribble, P. L., & Ostry, D. J. (1996). Origins of the
power law relation between movement velocity and curvature: modeling the
effects of muscle mechanics and limb dynamics. Journal of Neurophysiology,
76(5), 2853-2860 that define the variables V and R that are going to be used in the analysis to see if the relatoiship between them fits the power law.

RM: Do you agree that these are the formulas for computing V and R or is this paper the wrong reference to use for those formulas?

Best

Rick

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

let it be, rick. let it be.

image322.png

···

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

MT: In my view, Rick is a great experimenter and producer of lovely

demos of PCT, but he is no mathematician and no theorist.

To allow

his idiosyncratic private theories of mathematical relationships to
stand as though they were acceptable would be simply irresponsible.

RM: OK, let’s try this again slowly so you can show me where my mistake is. Let’s start by making sure that I’m using the right equations. Here are the two equations from Gribble, P. L., & Ostry, D. J. (1996). Origins of the
power law relation between movement velocity and curvature: modeling the
effects of muscle mechanics and limb dynamics. Journal of Neurophysiology,
76(5), 2853-2860 that define the variables V and R that are going to be used in the analysis to see if the relatoiship between them fits the power law.

RM: Do you agree that these are the formulas for computing V and R or is this paper the wrong reference to use for those formulas?

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Rick Marken (2016.09.13.0800)]

image322.png

···

On Mon, Sep 12, 2016 at 11:23 PM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

AGM: let it be, rick. let it be.

RM: I love the song but I’d rather just have an answer to my question. You claim that my math is wrong and I would simply like to find out what’s wrong with it.

Best

Rick

On Tuesday, 13 September 2016, Richard Marken rsmarken@gmail.com wrote:

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

MT: In my view, Rick is a great experimenter and producer of lovely

demos of PCT, but he is no mathematician and no theorist.

To allow

his idiosyncratic private theories of mathematical relationships to
stand as though they were acceptable would be simply irresponsible.

RM: OK, let’s try this again slowly so you can show me where my mistake is. Let’s start by making sure that I’m using the right equations. Here are the two equations from Gribble, P. L., & Ostry, D. J. (1996). Origins of the
power law relation between movement velocity and curvature: modeling the
effects of muscle mechanics and limb dynamics. Journal of Neurophysiology,
76(5), 2853-2860 that define the variables V and R that are going to be used in the analysis to see if the relatoiship between them fits the power law.

RM: Do you agree that these are the formulas for computing V and R or is this paper the wrong reference to use for those formulas?

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

no you don’t. you just want to play the game. you have had your chances. if you want to learn, read some of the power law papers i had sent and, why not, some of the many emails i have sent as well.

image322.png

···

On Mon, Sep 12, 2016 at 11:23 PM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

AGM: let it be, rick. let it be.

RM: I love the song but I’d rather just have an answer to my question. You claim that my math is wrong and I would simply like to find out what’s wrong with it.

Best

Rick

On Tuesday, 13 September 2016, Richard Marken rsmarken@gmail.com wrote:


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

MT: In my view, Rick is a great experimenter and producer of lovely

demos of PCT, but he is no mathematician and no theorist.

To allow

his idiosyncratic private theories of mathematical relationships to
stand as though they were acceptable would be simply irresponsible.

RM: OK, let’s try this again slowly so you can show me where my mistake is. Let’s start by making sure that I’m using the right equations. Here are the two equations from Gribble, P. L., & Ostry, D. J. (1996). Origins of the
power law relation between movement velocity and curvature: modeling the
effects of muscle mechanics and limb dynamics. Journal of Neurophysiology,
76(5), 2853-2860 that define the variables V and R that are going to be used in the analysis to see if the relatoiship between them fits the power law.

RM: Do you agree that these are the formulas for computing V and R or is this paper the wrong reference to use for those formulas?

Best

Rick


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[Martin Taylor 2016.09.13.

I said that we had tried "sic ways from Sunday" to get across the

same point. Thanks for pointing the way to a “Sunday version”.

These formulas are correct when used in the way G+O used them. But

they do tend to lead one astray when the context becomes more
general. As I said very early in the thread, it’s a very easy
mistake to make.

What's wrong with plugging the value of V from (8) into the equation

for R (9)? Nothing, if all you want to do, as is the case for G+O,
is to compute the curvature at a point where the observed velocity
was V, which they computed from (8). It’s fine, because you can use
any value of V at all in (9). What you can’t do is work backwards
from (9) to generate a specific value of V. It’s a subtle variant of
the “divide by zero” error.

A crude version of the "divide by zero" error goes like this:

x/a = w
y/a = z

If w = z, then x = y

x/0 = infinity
3/0 = infinity

infinity = infinity
Hence x = 3

but also

x/0 = infinity
4/0 = infinity

Hence x = 4, but since also x = 3, therefore 3 = 4.

The problem there is that infinity*c = infinity for all c, so the

original “if-then” statement is wrong. It should read “If (w = z AND
w != 0) then x = y”. Most times, the “divide by zero” error occurs
much more subtly and is often hard to find in a convoluted proof
that is actually wrong despite looking formally correct.

What you have in the G+O pair of equations is a similar situation,

though the problem is compounded by a perceptual problem in the
notation, which is Newton’s “dotty” rather than Leibnits’s explicit
notation. Typically we use the dot notation to specify
differentiation with respect to time. If the variable being
differentiated is a spatial extent, then the first derivative is a
velocity in the direction represented by that variable and the
second derivative is an acceleration in the same direction. That’s
what Newton wanted for his planetary orbits and falling apples, and
that’s what G+O wanted in order to measure the along-track velocity
pattern of their moving object (finger, I guess, though the paper
isn’t explicit). They didn’t have an accelerometer attached to the
finger, but they could handily determine its position in x and y,
and Euclid allowed them to compute the along-track velocity and
acceleration by taking the square root of the sum of squares. That
gave them equation (8).

Now we have to see how they came to equation (9). That's a bit more

complicated, so please bear with me.

They presumably either used someone else's derivation or made their

own, starting from one of several equivalent measures of curvature,
one of which is C = 1/R where R is the radius of the osculating
circle at the point of concern. Another one is developed using
vector calculus, which I have no intention of introducing into this
discussion. It is C = dx/ds*d2y/ds2 - dy/ds *
d2x/ds2 , where s is distance along the curve
from some arbitrary starting point.

For G+O this formula was not very convenient, because they would

have had to measure these first and second derivatives of x and y
with respect to distance along the curve fairly accurately. But they
had a trick available, in the “chain rule” of differentiation:
dx/dydy/dz = dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first derivative gives you
the rule for the second derivative, and so on. For the second
derivative the rule is (d2x/dy2)
(dy/dz)2
= d2x/dz2.

Using the chain rule, G+O could multiply the formula for C by

(ds/dz}3/(ds/dz)3 = 1, for any variable z that
allowed the differentiation, to get C = ((dx/ds)(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3
- (dy/ds)(ds/dz)(d2x/ds2)*(ds/dz)3)/(ds/dz)3 .
This formula is true (allowing for typos) for variable “z” whatever
(as with the divide by zero example), but it wouldn’t have helped
G+O very much, had it not been that for one particular variable they
already had measures they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they
had obtained from their observations of movement. Using those
measures, they could set “z” = t (time), making dx/dt =
dx/ds*ds/dt. They could then take advantage of their measured
velocities to substitute for ds/dt, and write

C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>

Oh goody! We don't have to measure anything new to get our

curvatures. We can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing, because it made the
published equations look as though the V3/V3
multiplier was special to the velocities they measured, whereas it
was simply a convenient choice from a literally infinite variety of
choices they could have made. G+O made it even more confusing in the
publication by using the Newton dotty notation, which made it look
as though there was something necessary about the time
differentiation in the curvature equation.

When we put all this together, we come to the way this is a variant

of the “divide by zero” error. That error depends on the fact that
you can put any variable at all in for “x” in “x/0 = infinity”. The
– shall we call it – the “curvature error” depends on the fact
that you can use anything at all for V (including the measured
values), provided only that V is defined as ds/dz where z is some
variable for which ds/dz exists everywhere. You therefore cannot use
the curvature equation in any way to determine V.

Does this "Sunday" explanation help?

Martin

image322.png

···

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

            MT: In my view, Rick is a great experimenter and

producer of lovely demos of PCT, but he is no
mathematician and no theorist.

            To allow his idiosyncratic private

theories of mathematical relationships to stand as
though they were acceptable would be simply
irresponsible.

            RM: OK, let's

try this again slowly so you can show me where my
mistake is. Let’s start by making sure that I’m using
the right equations. Here are the two equations from
Gribble, P. L., & Ostry, D. J. (1996). Origins of
the
power law relation between movement velocity and
curvature: modeling the
effects of muscle mechanics and limb dynamics. J* ournal
of Neurophysiology* ,
76(5), 2853-2860 that define the variables V and R that
are going to be used in the analysis to see if the
relatoiship between them fits the power law.

      RM: Do you agree that these are the formulas for computing V

and R or is this paper the wrong reference to use for those
formulas?

martin, i applaud your dedication, but if basic maths are missed, there is little hope. why not starting more phenomenological by UNDERSTANDING what curvature is and then realize that curvature is a property of the ink on a paper once it is dry, whereas speed is not in the ink…!! then one KNOWS that mathematically speed does not determine curvature, nor the converse.

then we can move to physics, and then to bio and psychology.

image322.png

···

[From Rick Marken (2016.09.12.1750)]

Martin Taylor (2016.09.12.12.15) –

            MT: In my view, Rick is a great experimenter and

producer of lovely demos of PCT, but he is no
mathematician and no theorist.

            To allow his idiosyncratic private

theories of mathematical relationships to stand as
though they were acceptable would be simply
irresponsible.

            RM: OK, let's

try this again slowly so you can show me where my
mistake is. Let’s start by making sure that I’m using
the right equations. Here are the two equations from
Gribble, P. L., & Ostry, D. J. (1996). Origins of
the
power law relation between movement velocity and
curvature: modeling the
effects of muscle mechanics and limb dynamics. J* ournal
of Neurophysiology* ,
76(5), 2853-2860 that define the variables V and R that
are going to be used in the analysis to see if the
relatoiship between them fits the power law.

      RM: Do you agree that these are the formulas for computing V

and R or is this paper the wrong reference to use for those
formulas?

[From Rick Marken (2016.09.13.1320)]

image322.png

···

Martin Taylor (2016.09.13.)–

MT: These formulas are correct when used in the way G+O used them.

RM: OK, since G+O used these formulas to compute V and R then they are correct.

MT: What's wrong with plugging the value of V from (8) into the equation

for R (9)? Nothing,

RM: Thank you. So no math error so far.

MT: if all you want to do, as is the case for G+O,

is to compute the curvature at a point where the observed velocity
was V, which they computed from (8).

RM: And that’s all I want to do. The formulas above are used by G+O to compute V and R that are then used in a regression analysis where log R is regressed on log V to determine the power coefficient relating these variables.

MT: It's fine, because you can use

any value of V at all in (9). What you can’t do is work backwards
from (9) to generate a specific value of V. It’s a subtle variant of
the “divide by zero” error.

RM: But I’m not “working back” from equation 9. I’m just showing what the relationship between V and R (as measured above) is expected to be based on solving for the algebraic relationship between these variables. This was done by plugging V from equation 8 into the equation 9 for R, which you agreed is perfectly correct. So where is the math error?

MT: A crude version of the “divide by zero” error goes like this:

x/a = w

y/a = z



If w = z, then x = y



x/0 = infinity

3/0 = infinity



infinity = infinity

Hence x = 3



but also



x/0 = infinity

4/0 = infinity



Hence x = 4, but since also x = 3, therefore 3 = 4.



The problem there is that infinity*c = infinity for all c, so the

original “if-then” statement is wrong. It should read “If (w = z AND
w != 0) then x = y”. Most times, the “divide by zero” error occurs
much more subtly and is often hard to find in a convoluted proof
that is actually wrong despite looking formally correct.

RM: But there is no “divide by zero” problem in the algebraic relationship between V and R. This is proven by the fact that the linear version of my derived equation for the relationship between V and R:

log (V) = 1/3log (D) + 1/3log (R)

perfectly accounts for the variance in log(V) for all curved movement trajectories (with no straight line segments). There is no division by zero error when this equation is used to compute log (V) as a function of log (D) and log (R).

MT: What you have in the G+O pair of equations is a similar situation,

though the problem is compounded by a perceptual problem in the
notation, which is Newton’s “dotty” rather than Leibnits’s explicit
notation. Typically we use the dot notation to specify
differentiation with respect to time. If the variable being
differentiated is a spatial extent, then the first derivative is a
velocity in the direction represented by that variable and the
second derivative is an acceleration in the same direction.

RM: This is not a “perceptual problem”. What you are saying is that the equations above are not the correct equations; that X.dot and Y.dot are not the same variables in the two equations. In one case they are a time derivative and in the other spatial derivatives. If that is true then it is not possible to write V as a function of R. But I think it is very unlikely that G+O would usethe same symbol for two different variables. It’s unlikely for a couple reasons. First, I don’t think G+O would have wanted to confuse their readers that way. And, second, I can replicate their results perfectly when when I measure V and R using time derivatives in the computation of both V and R. So I don’t buy the argument that X.dot and Y.dot are different variables in the two equations. But if it turns out to be correct – if, indeed, X.dot and Y.dot refer to different variables in equations 8 and 9 – then it would certainly not be a “math error” on my part to have treated them as being the same. I think the “error” would be on G+O for using the same symbol to refer to two different variables.

MT: That's

what Newton wanted for his planetary orbits and falling apples, and
that’s what G+O wanted in order to measure the along-track velocity
pattern of their moving object (finger, I guess, though the paper
isn’t explicit). They didn’t have an accelerometer attached to the
finger, but they could handily determine its position in x and y,
and Euclid allowed them to compute the along-track velocity and
acceleration by taking the square root of the sum of squares. That
gave them equation (8).

MT: Now we have to see how they came to equation (9). That's a bit more

complicated, so please bear with me.

RM: I don’t think that’s necessary. Equations 8 and 9 are what they are. I think your main argument is that my derivation of the algebraic relationship between V and R is an “error” because X.dot and Y. dot refer to different variables in the two equations. If this is true (and I think it’s not) then I have not made a math error; I have been fooled by G + O’s confusing notation.

RM: So I guess what I need to know is what you think are the correct computational formulas for V and R. How did G+O actually compute them? I think all this would involve is showing me how to compute X.dot and Y.dot (and X.dot dot and Y dot dot) in equations 8 and 9.

Best

Rick

They presumably either used someone else's derivation or made their

own, starting from one of several equivalent measures of curvature,
one of which is C = 1/R where R is the radius of the osculating
circle at the point of concern. Another one is developed using
vector calculus, which I have no intention of introducing into this
discussion. It is C = dx/ds*d2y/ds2 - dy/ds *
d2x/ds2 , where s is distance along the curve
from some arbitrary starting point.

For G+O this formula was not very convenient, because they would

have had to measure these first and second derivatives of x and y
with respect to distance along the curve fairly accurately. But they
had a trick available, in the “chain rule” of differentiation:
dx/dydy/dz = dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first derivative gives you
the rule for the second derivative, and so on. For the second
derivative the rule is (d2x/dy2)
(dy/dz)2
= d2x/dz2.

Using the chain rule, G+O could multiply the formula for C by

(ds/dz}3/(ds/dz)3 = 1, for any variable z that
allowed the differentiation, to get C = ((dx/ds)(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3
- (dy/ds)(ds/dz)(d2x/ds2)*(ds/dz)3)/(ds/dz)3 .
This formula is true (allowing for typos) for variable “z” whatever
(as with the divide by zero example), but it wouldn’t have helped
G+O very much, had it not been that for one particular variable they
already had measures they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they
had obtained from their observations of movement. Using those
measures, they could set “z” = t (time), making dx/dt =
dx/ds*ds/dt. They could then take advantage of their measured
velocities to substitute for ds/dt, and write

C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>



Oh goody! We don't have to measure anything new to get our

curvatures. We can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing, because it made the
published equations look as though the V3/V3
multiplier was special to the velocities they measured, whereas it
was simply a convenient choice from a literally infinite variety of
choices they could have made. G+O made it even more confusing in the
publication by using the Newton dotty notation, which made it look
as though there was something necessary about the time
differentiation in the curvature equation.

When we put all this together, we come to the way this is a variant

of the “divide by zero” error. That error depends on the fact that
you can put any variable at all in for “x” in “x/0 = infinity”. The
– shall we call it – the “curvature error” depends on the fact
that you can use anything at all for V (including the measured
values), provided only that V is defined as ds/dz where z is some
variable for which ds/dz exists everywhere. You therefore cannot use
the curvature equation in any way to determine V.

Does this "Sunday" explanation help?



Martin


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

      RM: Do you agree that these are the formulas for computing V

and R or is this paper the wrong reference to use for those
formulas?

a-g-a-i-n: This is still an amazing demo on how to use rhetoric to defend mathematical flaws, lack of physical insight and unwillingness for phenomenological effort.

image322.png

···

On Tue, Sep 13, 2016 at 10:20 PM, Richard Marken rsmarken@gmail.com wrote:

[From Rick Marken (2016.09.13.1320)]

Martin Taylor (2016.09.13.)–

MT: These formulas are correct when used in the way G+O used them.

RM: OK, since G+O used these formulas to compute V and R then they are correct.

MT: What's wrong with plugging the value of V from (8) into the equation

for R (9)? Nothing,

RM: Thank you. So no math error so far.

MT: if all you want to do, as is the case for G+O,

is to compute the curvature at a point where the observed velocity
was V, which they computed from (8).

RM: And that’s all I want to do. The formulas above are used by G+O to compute V and R that are then used in a regression analysis where log R is regressed on log V to determine the power coefficient relating these variables.

MT: It's fine, because you can use

any value of V at all in (9). What you can’t do is work backwards
from (9) to generate a specific value of V. It’s a subtle variant of
the “divide by zero” error.

RM: But I’m not “working back” from equation 9. I’m just showing what the relationship between V and R (as measured above) is expected to be based on solving for the algebraic relationship between these variables. This was done by plugging V from equation 8 into the equation 9 for R, which you agreed is perfectly correct. So where is the math error?

MT: A crude version of the “divide by zero” error goes like this:

x/a = w

y/a = z



If w = z, then x = y



x/0 = infinity

3/0 = infinity



infinity = infinity

Hence x = 3



but also



x/0 = infinity

4/0 = infinity



Hence x = 4, but since also x = 3, therefore 3 = 4.



The problem there is that infinity*c = infinity for all c, so the

original “if-then” statement is wrong. It should read “If (w = z AND
w != 0) then x = y”. Most times, the “divide by zero” error occurs
much more subtly and is often hard to find in a convoluted proof
that is actually wrong despite looking formally correct.

RM: But there is no “divide by zero” problem in the algebraic relationship between V and R. This is proven by the fact that the linear version of my derived equation for the relationship between V and R:

log (V) = 1/3log (D) + 1/3log (R)

perfectly accounts for the variance in log(V) for all curved movement trajectories (with no straight line segments). There is no division by zero error when this equation is used to compute log (V) as a function of log (D) and log (R).

MT: What you have in the G+O pair of equations is a similar situation,

though the problem is compounded by a perceptual problem in the
notation, which is Newton’s “dotty” rather than Leibnits’s explicit
notation. Typically we use the dot notation to specify
differentiation with respect to time. If the variable being
differentiated is a spatial extent, then the first derivative is a
velocity in the direction represented by that variable and the
second derivative is an acceleration in the same direction.

RM: This is not a “perceptual problem”. What you are saying is that the equations above are not the correct equations; that X.dot and Y.dot are not the same variables in the two equations. In one case they are a time derivative and in the other spatial derivatives. If that is true then it is not possible to write V as a function of R. But I think it is very unlikely that G+O would usethe same symbol for two different variables. It’s unlikely for a couple reasons. First, I don’t think G+O would have wanted to confuse their readers that way. And, second, I can replicate their results perfectly when when I measure V and R using time derivatives in the computation of both V and R. So I don’t buy the argument that X.dot and Y.dot are different variables in the two equations. But if it turns out to be correct – if, indeed, X.dot and Y.dot refer to different variables in equations 8 and 9 – then it would certainly not be a “math error” on my part to have treated them as being the same. I think the “error” would be on G+O for using the same symbol to refer to two different variables.

MT: That's

what Newton wanted for his planetary orbits and falling apples, and
that’s what G+O wanted in order to measure the along-track velocity
pattern of their moving object (finger, I guess, though the paper
isn’t explicit). They didn’t have an accelerometer attached to the
finger, but they could handily determine its position in x and y,
and Euclid allowed them to compute the along-track velocity and
acceleration by taking the square root of the sum of squares. That
gave them equation (8).

MT: Now we have to see how they came to equation (9). That's a bit more

complicated, so please bear with me.

RM: I don’t think that’s necessary. Equations 8 and 9 are what they are. I think your main argument is that my derivation of the algebraic relationship between V and R is an “error” because X.dot and Y. dot refer to different variables in the two equations. If this is true (and I think it’s not) then I have not made a math error; I have been fooled by G + O’s confusing notation.

RM: So I guess what I need to know is what you think are the correct computational formulas for V and R. How did G+O actually compute them? I think all this would involve is showing me how to compute X.dot and Y.dot (and X.dot dot and Y dot dot) in equations 8 and 9.

Best

Rick

They presumably either used someone else's derivation or made their

own, starting from one of several equivalent measures of curvature,
one of which is C = 1/R where R is the radius of the osculating
circle at the point of concern. Another one is developed using
vector calculus, which I have no intention of introducing into this
discussion. It is C = dx/ds*d2y/ds2 - dy/ds *
d2x/ds2 , where s is distance along the curve
from some arbitrary starting point.

For G+O this formula was not very convenient, because they would

have had to measure these first and second derivatives of x and y
with respect to distance along the curve fairly accurately. But they
had a trick available, in the “chain rule” of differentiation:
dx/dydy/dz = dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first derivative gives you
the rule for the second derivative, and so on. For the second
derivative the rule is (d2x/dy2)
(dy/dz)2
= d2x/dz2.

Using the chain rule, G+O could multiply the formula for C by

(ds/dz}3/(ds/dz)3 = 1, for any variable z that
allowed the differentiation, to get C = ((dx/ds)(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3
- (dy/ds)(ds/dz)(d2x/ds2)*(ds/dz)3)/(ds/dz)3 .
This formula is true (allowing for typos) for variable “z” whatever
(as with the divide by zero example), but it wouldn’t have helped
G+O very much, had it not been that for one particular variable they
already had measures they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they
had obtained from their observations of movement. Using those
measures, they could set “z” = t (time), making dx/dt =
dx/ds*ds/dt. They could then take advantage of their measured
velocities to substitute for ds/dt, and write

C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>



Oh goody! We don't have to measure anything new to get our

curvatures. We can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing, because it made the
published equations look as though the V3/V3
multiplier was special to the velocities they measured, whereas it
was simply a convenient choice from a literally infinite variety of
choices they could have made. G+O made it even more confusing in the
publication by using the Newton dotty notation, which made it look
as though there was something necessary about the time
differentiation in the curvature equation.

When we put all this together, we come to the way this is a variant

of the “divide by zero” error. That error depends on the fact that
you can put any variable at all in for “x” in “x/0 = infinity”. The
– shall we call it – the “curvature error” depends on the fact
that you can use anything at all for V (including the measured
values), provided only that V is defined as ds/dz where z is some
variable for which ds/dz exists everywhere. You therefore cannot use
the curvature equation in any way to determine V.

Does this "Sunday" explanation help?



Martin


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

      RM: Do you agree that these are the formulas for computing V

and R or is this paper the wrong reference to use for those
formulas?

[Martin Taylor 2016.09.13.16.28]

[From Rick Marken (2016.09.13.1320)]

You know how they computed the formulas if you read my message. How

they found xdot etc. is as simple as you would expect. They measured
where the moving object was in x and y at t0 and t1 and divided the
distance by the time difference.

Especially in light of Barb's comment, I don't want to be rude, but

what I need to know is when (or perhaps “if”) you will actually read
AND think about what I wrote in the message to which you claim to be
responding (and, I suppose, any other message in which this same
point was explained in a different way). I had thought of saying to
Alex that your first “Math Mistakes” message was an encouraging sign
that you really wanted to learn, after he said “no you don’t. you
just want to play the game”, but now I’m glad I didn’t. His response
apparently was correct and mine was not.

I don't think I want to say any more about your approach to

curvature and the power law until I have evidence that you have
actually internalized just one of those messages. On the topic of
the power law I will simply work on a real PCT explanation,
whatever it turns out to be. Suggesting appropriate experiments to
find the controlled variable(s) is the sort of thing you are good
at. I have proposed a couple in the course of these many threads,
but I’m sure you could think of more and better ones if you gave up
on your “D” variable, which I have shown you in several messages
including this last, is just V3 /R, where V is an
arbitrary variable that is the value of a derivative of the form
ds/dz", z being another arbitrary variable.

Martin

image322.png

···

Martin Taylor (2016.09.13.)–

            MT: These formulas are correct when used in the

way G+O used them.

                    RM: Do you agree that these are the formulas for

computing V and R or is this paper the wrong
reference to use for those formulas?

          RM: So I guess what I need to know is what you think

are the correct computational formulas for V and R. How
did G+O actually compute them? I think all this would
involve is showing me how to compute X.dot and Y.dot (and
X.dot dot and Y dot dot) in equations 8 and 9.

[From Rick Marken (2016.09.13.1350)]

···

Martin Taylor (2016.09.13.16.28)–

MT: You know how they computed the formulas if you read my message. How

they found xdot etc. is as simple as you would expect. They measured
where the moving object was in x and y at t0 and t1 and divided the
distance by the time difference.

RM: Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for both equations 8 and 9?

Best

Rick

Especially in light of Barb's comment, I don't want to be rude, but

what I need to know is when (or perhaps “if”) you will actually read
AND think about what I wrote in the message to which you claim to be
responding (and, I suppose, any other message in which this same
point was explained in a different way). I had thought of saying to
Alex that your first “Math Mistakes” message was an encouraging sign
that you really wanted to learn, after he said “no you don’t. you
just want to play the game”, but now I’m glad I didn’t. His response
apparently was correct and mine was not.

I don't think I want to say any more about your approach to

curvature and the power law until I have evidence that you have
actually internalized just one of those messages. On the topic of
the power law I will simply work on a real PCT explanation,
whatever it turns out to be. Suggesting appropriate experiments to
find the controlled variable(s) is the sort of thing you are good
at. I have proposed a couple in the course of these many threads,
but I’m sure you could think of more and better ones if you gave up
on your “D” variable, which I have shown you in several messages
including this last, is just V3 /R, where V is an
arbitrary variable that is the value of a derivative of the form
ds/dz", z being another arbitrary variable.

Martin

          RM: So I guess what I need to know is what you think

are the correct computational formulas for V and R. How
did G+O actually compute them? I think all this would
involve is showing me how to compute X.dot and Y.dot (and
X.dot dot and Y dot dot) in equations 8 and 9.

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

How can we be discussing for what must be now of the order of a hundred emails and only now you seem to get that xdot a ydot are time derivatives? What did you think that was in the mathematical formula, the position of the larva with a dot painted on its head?! That is precisely what I mean: the habit of spitting out PCT phrases when you have really no clue about the specific matter you are talking about! More than annoying, this is very very very worrisome.

···

On Tue, Sep 13, 2016 at 10:52 PM, Richard Marken rsmarken@gmail.com wrote:

[From Rick Marken (2016.09.13.1350)]

Martin Taylor (2016.09.13.16.28)–

MT: You know how they computed the formulas if you read my message. How

they found xdot etc. is as simple as you would expect. They measured
where the moving object was in x and y at t0 and t1 and divided the
distance by the time difference.

RM: Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for both equations 8 and 9?

Best

Rick

Especially in light of Barb's comment, I don't want to be rude, but

what I need to know is when (or perhaps “if”) you will actually read
AND think about what I wrote in the message to which you claim to be
responding (and, I suppose, any other message in which this same
point was explained in a different way). I had thought of saying to
Alex that your first “Math Mistakes” message was an encouraging sign
that you really wanted to learn, after he said “no you don’t. you
just want to play the game”, but now I’m glad I didn’t. His response
apparently was correct and mine was not.

I don't think I want to say any more about your approach to

curvature and the power law until I have evidence that you have
actually internalized just one of those messages. On the topic of
the power law I will simply work on a real PCT explanation,
whatever it turns out to be. Suggesting appropriate experiments to
find the controlled variable(s) is the sort of thing you are good
at. I have proposed a couple in the course of these many threads,
but I’m sure you could think of more and better ones if you gave up
on your “D” variable, which I have shown you in several messages
including this last, is just V3 /R, where V is an
arbitrary variable that is the value of a derivative of the form
ds/dz", z being another arbitrary variable.

Martin


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

          RM: So I guess what I need to know is what you think

are the correct computational formulas for V and R. How
did G+O actually compute them? I think all this would
involve is showing me how to compute X.dot and Y.dot (and
X.dot dot and Y dot dot) in equations 8 and 9.

[Martin Taylor 2016.09.13.18.07]

I said I had finished with this argument, but…

[From Rick Marken (2016.09.13.1350)]

Martin Taylor (2016.09.13.16.28)–

      MT: You know how they computed the formulas if you read

my message. How they found xdot etc. is as simple as you would
expect. They measured where the moving object was in x and y
at t0 and t1 and divided the distance by the time difference.

    RM: Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and

Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for
both equations 8 and 9?

Yes, but the critical point of my suggestion that you read my

earlier message is contained in this:

[From Rick Marken (2016.09.13.1320)]

      MT: Now we have to see how they came to equation (9). That's a

bit more complicated, so please bear with me.

    RM: I don't think that's necessary. Equations 8 and 9 are

what they are.

But it is necessary. In fact it's the whole point, the core of two

months of argument.

Martin
···

RM: So I guess what I need to know is what you
think are the correct computational formulas for V
and R. How did G+O actually compute them? I think
all this would involve is showing me how to
compute X.dot and Y.dot (and X.dot dot and Y dot
dot) in equations 8 and 9.

[From Rick Marken (2016.09.13.1515)]

···

On Tue, Sep 13, 2016 at 2:22 PM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

AGM: How can we be discussing for what must be now of the order of a hundred emails and only now you seem to get that xdot a ydot are time derivatives?

RM: I’ve known they were time derivatives all along. But Martin said that X.dot and Y.dot were different derivatives in the equations for V and R. So I asked him to show me “how to compute X.dot and Y.dot (and X.dot dot and Y dot dot) in equations 8 and 9.” And this was his answer:

MT: You know how they computed the formulas if you read my message. How they found xdot etc. is as simple as you would expect. They measured where the moving object was in x and y at t0 and t1 and divided the distance by the time difference.

RM: So my reply was: “Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for both equations 8 and 9?”. I asked this because it sounded like Martin was now saying that X.dot and Y.dot were time derivatives (which is what I thought they were all along and had computed them that way in my analysis) and that they were the same variable in both the equation for V (8) and for R (9), as I have also assumed all along.

AGM: That is precisely what I mean: the habit of spitting out PCT phrases when you have really no clue about the specific matter you are talking about!

RM: I didn’t know that saying “I assumed that X.dot and Y.dot were the same variables in two different equations” was a PCT phrase.

Best

Rick

On Tue, Sep 13, 2016 at 10:52 PM, Richard Marken rsmarken@gmail.com wrote:

[From Rick Marken (2016.09.13.1350)]

Martin Taylor (2016.09.13.16.28)–

MT: You know how they computed the formulas if you read my message. How

they found xdot etc. is as simple as you would expect. They measured
where the moving object was in x and y at t0 and t1 and divided the
distance by the time difference.

RM: Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for both equations 8 and 9?

Best

Rick

Especially in light of Barb's comment, I don't want to be rude, but

what I need to know is when (or perhaps “if”) you will actually read
AND think about what I wrote in the message to which you claim to be
responding (and, I suppose, any other message in which this same
point was explained in a different way). I had thought of saying to
Alex that your first “Math Mistakes” message was an encouraging sign
that you really wanted to learn, after he said “no you don’t. you
just want to play the game”, but now I’m glad I didn’t. His response
apparently was correct and mine was not.

I don't think I want to say any more about your approach to

curvature and the power law until I have evidence that you have
actually internalized just one of those messages. On the topic of
the power law I will simply work on a real PCT explanation,
whatever it turns out to be. Suggesting appropriate experiments to
find the controlled variable(s) is the sort of thing you are good
at. I have proposed a couple in the course of these many threads,
but I’m sure you could think of more and better ones if you gave up
on your “D” variable, which I have shown you in several messages
including this last, is just V3 /R, where V is an
arbitrary variable that is the value of a derivative of the form
ds/dz", z being another arbitrary variable.

Martin


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

          RM: So I guess what I need to know is what you think

are the correct computational formulas for V and R. How
did G+O actually compute them? I think all this would
involve is showing me how to compute X.dot and Y.dot (and
X.dot dot and Y dot dot) in equations 8 and 9.

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Rick Marken (2016.09.13.1520)]

···

Martin Taylor (2016.09.13.18.07)-

    RM: Thanks Martin. So X.dot = (X.t-X.t-1)/[t-(t-1)] and

Y.dot = (Y.t-Y.t-1)/[t-(t-1)] . Is that right? Is that true for
both equations 8 and 9?

MT: Yes,

RM: So X.dot and Y.dot are time derivatives and they are the same time derivatives in the equations for V (8) and R (9). So there is no math error.

MT: but the critical point of my suggestion that you read my

earlier message is contained in this:

RM: Contained in what? It was just blank after “this”. Are you finally going to show me my math error or are you just going to keep telling me (and everyone else) that I made one and that I’m being stubborn for not recognizing it?

Best

Rick

[From Rick Marken (2016.09.13.1320)]

      MT: Now we have to see how they came to equation (9). That's a

bit more complicated, so please bear with me.

    RM: I don't think that's necessary. Equations 8 and 9 are

what they are.

But it is necessary. In fact it's the whole point, the core of two

months of argument.

Martin

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[From Rick Marken (2016.09.13.1610)]

···

RM: Oh, I see. It’s contained in this:

MT: Now we have to see how they came to equation (9). That’s a bit more complicated, so please bear with me.

MT: They presumably either used someone else’s derivation or made their own, starting from one of several equivalent measures of curvature, one of which is C = 1/R where R is the radius of the osculating circle at the point of concern. Another one is developed using vector calculus, which I have no intention of introducing into this discussion. It is C = dx/dsd2y/ds2 - dy/ds * d2x/ds2, where s is distance along the curve from some arbitrary starting point.
For G+O this formula was not very convenient, because they would have had to measure these first and second derivatives of x and y with respect to distance along the curve fairly accurately. But they had a trick available, in the “chain rule” of differentiation: dx/dy
dy/dz = dx/dz. The "dy"s cancel out just like ordinary variables. Using the chain rule on the first derivative gives you the rule for the second derivative, and so on. For the second derivative the rule is (d2x/dy2)(dy/dz)2 = d2x/dz2.
Using the chain rule, G+O could multiply the formula for C by (ds/dz}3/(ds/dz)3 = 1, for any variable z that allowed the differentiation, to get C = ((dx/ds)
(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3 - (dy/ds)(ds/dz)(d2x/ds2)__(ds/dz)__3)/(ds/dz)3. This formula is true (allowing for typos) for variable “z” whatever (as with the divide by zero example), but it wouldn’t have helped G+O very much, had it not been that for one particular variable they already had measures they could use. Those measures were the ds/dt velocity and the derived d2s/dt2 values they had obtained from their observations of movement. Using those measures, they could set “z” = t (time), making dx/dt = dx/dsds/dt. They could then take advantage of their measured velocities to substitute for ds/dt, and write
C = (dx/dt
d2y/dt2)/V3 - (dy/dt*d2y/dt2)/V3
Oh goody! We don’t have to measure anything new to get our curvatures. We can use the values of dx/dt and dy/dt that we got before! Very handy. … But also very confusing, because it made the published equations look as though the V3/V3 multiplier was special to the velocities they measured, whereas it was simply a convenient choice from a literally infinite variety of choices they could have made. G+O made it even more confusing in the publication by using the Newton dotty notation, which made it look as though there was something necessary about the time differentiation in the curvature equation.
When we put all this together, we come to the way this is a variant of the “divide by zero” error. That error depends on the fact that you can put any variable at all in for “x” in “x/0 = infinity”. The – shall we call it – the “curvature error” depends on the fact that you can use anything at all for V (including the measured values), provided only that V is defined as ds/dz where z is some variable for which ds/dz exists everywhere. You therefore cannot use the curvature equation in any way to determine V.
Does this “Sunday” explanation help?

RM: Not really. Are you saying that G+O used the wrong formulas for V and R? Or that the formulas they published are not actually the ones they used to compute V and R? Or that there is no way to compute R since we can’t measure ds? Either way, you can’t say I made a math error since I did the math correctly on the formulas I was given. (And, as I mentioned, the results came out exactly right).

RM: Rather than saying that I was making a math error, it would have helped if you had just said: “these are the correct formulas for computing V and R” and showed me the formulas. That would have saved a lot of trouble. So how about it; what are the correct formulas for computing V and R?

Best

Rick

MT: but the critical point of my suggestion that you read my

earlier message is contained in this:

RM: Contained in what?


Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers

[Martin Taylor 2016.09.13.22.49]

[From Rick Marken (2016.09.13.1610)]

If you actually read and thought about what you quote, I cannot read

your question as anything other than a not too subtle joke, so I
have to assume that you either did not read it or the maths, which I
tried to explain at the most basic level O could manage without
seeming to insult you (which I was afraid I was doing anyway), was a
bit too deep for you.

 Isuggest you try again, concentrating on figuring out why this DOES

explain why you have been making the same kind of mistake as the
“divide by zero” error. Perhaps I should repeat the last lines: " When we put all this together, we come to
the way this is a variant of the “divide by zero” error. That
error depends on the fact that you can put any variable at all in
for “x” in “x/0 = infinity”. The – shall we call it – the
“curvature error” depends on the fact that you can use anything at
all for V (including the measured values), provided only that V is
defined as ds/dz where z is some variable for which ds/dz exists
everywhere. You therefore cannot use the curvature equation in any
way to determine V."

  I emphasize "IN ANY WAY". Since I may be a little too subtle when

I say this, it simply says that your equation V = D1/3*C1/3 means
nothing at all, because it is true when V is any variable at all
that satisfies a very loose condition. If it is a velocity it can
be any velocity at all, or it can be any value of any variable
(and here I will repeat myself) that depends on any other variable
“z” whatever for which ds/dz is everywhere calculable.

G+O showed the correct formulas, and I said so. You did the correct

FORMAL algebra. Your math error was and apparently continues to be
the equivalent of the “divide by zero” error, which also depends on
doing the algebra correctly. The “divide by zero” or its “curvature
error” equivalent is a math error if ever there was one. It could be
and should be easily correctable, but apparently it isn’t. I don’t
know why.

Martin
···

RM: Oh, I see. It’s contained in this:

                MT: Now we have to see how

they came to equation (9). That’s a bit more
complicated, so please bear with me.

                                  MT: They presumably

either used someone else’s derivation or made their
own, starting from one of several equivalent
measures of curvature, one of which is C = 1/R where
R is the radius of the osculating circle at the
point of concern. Another one is developed using
vector calculus, which I have no intention of
introducing into this discussion. It is C = dx/dsd2y/ds2 - dy/ds * d2x/ds2 , where s is distance along
the curve from some arbitrary starting point.
For G+O this formula
was not very convenient, because they would have had
to measure these first and second derivatives of x
and y with respect to distance along the curve
fairly accurately. But they had a trick available,
in the “chain rule” of differentiation: dx/dy
dy/dz
= dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first
derivative gives you the rule for the second
derivative, and so on. For the second derivative the
rule is (d2x/dy2)(dy/dz)2 = d2x/dz2.
Using the chain rule,
G+O could multiply the formula for C by (ds/dz}3/(ds/dz)3 = 1, for any variable z
that allowed the differentiation, to get C =
((dx/ds)
(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3 - (dy/ds)(ds/dz)(d2x/ds2)__(ds/dz)__3)/(ds/dz)3 . This formula is true
(allowing for typos) for variable “z” whatever (as
with the divide by zero example), but it wouldn’t
have helped G+O very much, had it not been that for
one particular variable they already had measures
they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they had obtained
from their observations of movement. Using those
measures, they could set “z” = t (time), making
dx/dt = dx/ds*ds/dt. They could then take advantage
of their measured velocities to substitute for
ds/dt, and write

              C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>

                                  Oh goody! We don't have

to measure anything new to get our curvatures. We
can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing,
because it made the published equations look as
though the V3/V3 multiplier was special to
the velocities they measured, whereas it was simply
a convenient choice from a literally infinite
variety of choices they could have made. G+O made it
even more confusing in the publication by using the
Newton dotty notation, which made it look as though
there was something necessary about the time
differentiation in the curvature equation.

                                  When we put all this

together, we come to the way this is a variant of
the “divide by zero” error. That error depends on
the fact that you can put any variable at all in for
“x” in “x/0 = infinity”. The – shall we call it –
the “curvature error” depends on the fact that you
can use anything at all for V (including the
measured values), provided only that V is defined as
ds/dz where z is some variable for which ds/dz
exists everywhere. You therefore cannot use the
curvature equation in any way to determine V.

              Does this "Sunday" explanation help?
              RM: Not really. Are you saying that G+O used the

wrong formulas for V and R? Or that the formulas they
published are not actually the ones they used to
compute V and R? Or that there is no way to compute R
since we can’t measure ds? Either way, you can’t say I
made a math error since I did the math correctly on
the formulas I was given. (And, as I mentioned, the
results came out exactly right).

                      MT: but the critical

point of my suggestion that you read my
earlier message is contained in this:

RM: Contained in what?

              RM: Rather than saying that I was making a math

error, it would have helped if you had just said:
“these are the correct formulas for computing V and R”
and showed me the formulas.

              That would have saved a lot of trouble. So how

about it; what are the correct formulas for computing
V and R?

Best

Rick


Richard S.
Marken

                                                "The childhood of

the human race is
far from over. We
have a long way to
go before most
people will
understand that what
they do for
others is just as
important to their
well-being as what
they do for
themselves." –
William T. Powers

Richard S. Marken

                                      "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand
that what they do for
others is just as important to
their well-being as what they
do for
themselves." – William T.
Powers

martin, the csgNet is now a hybrid of a basic math accademy with an entertainment program for writing and joking with those who write back. stay tuned!

···

RM: Oh, I see. It’s contained in this:

                MT: Now we have to see how

they came to equation (9). That’s a bit more
complicated, so please bear with me.

                                  MT: They presumably

either used someone else’s derivation or made their
own, starting from one of several equivalent
measures of curvature, one of which is C = 1/R where
R is the radius of the osculating circle at the
point of concern. Another one is developed using
vector calculus, which I have no intention of
introducing into this discussion. It is C = dx/dsd2y/ds2 - dy/ds * d2x/ds2 , where s is distance along
the curve from some arbitrary starting point.
For G+O this formula
was not very convenient, because they would have had
to measure these first and second derivatives of x
and y with respect to distance along the curve
fairly accurately. But they had a trick available,
in the “chain rule” of differentiation: dx/dy
dy/dz
= dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first
derivative gives you the rule for the second
derivative, and so on. For the second derivative the
rule is (d2x/dy2)(dy/dz)2 = d2x/dz2.
Using the chain rule,
G+O could multiply the formula for C by (ds/dz}3/(ds/dz)3 = 1, for any variable z
that allowed the differentiation, to get C =
((dx/ds)
(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3 - (dy/ds)(ds/dz)(d2x/ds2)__(ds/dz)__3)/(ds/dz)3 . This formula is true
(allowing for typos) for variable “z” whatever (as
with the divide by zero example), but it wouldn’t
have helped G+O very much, had it not been that for
one particular variable they already had measures
they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they had obtained
from their observations of movement. Using those
measures, they could set “z” = t (time), making
dx/dt = dx/ds*ds/dt. They could then take advantage
of their measured velocities to substitute for
ds/dt, and write

              C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>

                                  Oh goody! We don't have

to measure anything new to get our curvatures. We
can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing,
because it made the published equations look as
though the V3/V3 multiplier was special to
the velocities they measured, whereas it was simply
a convenient choice from a literally infinite
variety of choices they could have made. G+O made it
even more confusing in the publication by using the
Newton dotty notation, which made it look as though
there was something necessary about the time
differentiation in the curvature equation.

                                  When we put all this

together, we come to the way this is a variant of
the “divide by zero” error. That error depends on
the fact that you can put any variable at all in for
“x” in “x/0 = infinity”. The – shall we call it –
the “curvature error” depends on the fact that you
can use anything at all for V (including the
measured values), provided only that V is defined as
ds/dz where z is some variable for which ds/dz
exists everywhere. You therefore cannot use the
curvature equation in any way to determine V.

              Does this "Sunday" explanation help?
              RM: Not really. Are you saying that G+O used the

wrong formulas for V and R? Or that the formulas they
published are not actually the ones they used to
compute V and R? Or that there is no way to compute R
since we can’t measure ds? Either way, you can’t say I
made a math error since I did the math correctly on
the formulas I was given. (And, as I mentioned, the
results came out exactly right).

                      MT: but the critical

point of my suggestion that you read my
earlier message is contained in this:

RM: Contained in what?

              RM: Rather than saying that I was making a math

error, it would have helped if you had just said:
“these are the correct formulas for computing V and R”
and showed me the formulas.

              That would have saved a lot of trouble. So how

about it; what are the correct formulas for computing
V and R?

Best

Rick


Richard S. Marken

                                      "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand
that what they do for
others is just as important to
their well-being as what they
do for
themselves." – William T.
Powers


Richard S.
Marken

                                                "The childhood of

the human race is
far from over. We
have a long way to
go before most
people will
understand that what
they do for
others is just as
important to their
well-being as what
they do for
themselves." –
William T. Powers

In other words, join me in the efforts of these newly created and much needed ONG:

www.pleaseStopRCP.org

(RCP = Rhetoric Control Theory)

···

On Wed, Sep 14, 2016 at 8:38 AM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

martin, the csgNet is now a hybrid of a basic math accademy with an entertainment program for writing and joking with those who write back. stay tuned!

On Wednesday, 14 September 2016, Martin Taylor mmt-csg@mmtaylor.net wrote:

[Martin Taylor 2016.09.13.22.49]

[From Rick Marken (2016.09.13.1610)]

If you actually read and thought about what you quote, I cannot read

your question as anything other than a not too subtle joke, so I
have to assume that you either did not read it or the maths, which I
tried to explain at the most basic level O could manage without
seeming to insult you (which I was afraid I was doing anyway), was a
bit too deep for you.

 Isuggest you try again, concentrating on figuring out why this DOES

explain why you have been making the same kind of mistake as the
“divide by zero” error. Perhaps I should repeat the last lines: " When we put all this together, we come to
the way this is a variant of the “divide by zero” error. That
error depends on the fact that you can put any variable at all in
for “x” in “x/0 = infinity”. The – shall we call it – the
“curvature error” depends on the fact that you can use anything at
all for V (including the measured values), provided only that V is
defined as ds/dz where z is some variable for which ds/dz exists
everywhere. You therefore cannot use the curvature equation in any
way to determine V."

  I emphasize "IN ANY WAY". Since I may be a little too subtle when

I say this, it simply says that your equation V = D1/3*C1/3 means
nothing at all, because it is true when V is any variable at all
that satisfies a very loose condition. If it is a velocity it can
be any velocity at all, or it can be any value of any variable
(and here I will repeat myself) that depends on any other variable
“z” whatever for which ds/dz is everywhere calculable.

G+O showed the correct formulas, and I said so. You did the correct

FORMAL algebra. Your math error was and apparently continues to be
the equivalent of the “divide by zero” error, which also depends on
doing the algebra correctly. The “divide by zero” or its “curvature
error” equivalent is a math error if ever there was one. It could be
and should be easily correctable, but apparently it isn’t. I don’t
know why.

Martin

RM: Oh, I see. It’s contained in this:

                MT: Now we have to see how

they came to equation (9). That’s a bit more
complicated, so please bear with me.

                                  MT: They presumably

either used someone else’s derivation or made their
own, starting from one of several equivalent
measures of curvature, one of which is C = 1/R where
R is the radius of the osculating circle at the
point of concern. Another one is developed using
vector calculus, which I have no intention of
introducing into this discussion. It is C = dx/dsd2y/ds2 - dy/ds * d2x/ds2 , where s is distance along
the curve from some arbitrary starting point.
For G+O this formula
was not very convenient, because they would have had
to measure these first and second derivatives of x
and y with respect to distance along the curve
fairly accurately. But they had a trick available,
in the “chain rule” of differentiation: dx/dy
dy/dz
= dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first
derivative gives you the rule for the second
derivative, and so on. For the second derivative the
rule is (d2x/dy2)(dy/dz)2 = d2x/dz2.
Using the chain rule,
G+O could multiply the formula for C by (ds/dz}3/(ds/dz)3 = 1, for any variable z
that allowed the differentiation, to get C =
((dx/ds)
(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3 - (dy/ds)(ds/dz)(d2x/ds2)__(ds/dz)__3)/(ds/dz)3 . This formula is true
(allowing for typos) for variable “z” whatever (as
with the divide by zero example), but it wouldn’t
have helped G+O very much, had it not been that for
one particular variable they already had measures
they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they had obtained
from their observations of movement. Using those
measures, they could set “z” = t (time), making
dx/dt = dx/ds*ds/dt. They could then take advantage
of their measured velocities to substitute for
ds/dt, and write

              C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>

                                  Oh goody! We don't have

to measure anything new to get our curvatures. We
can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing,
because it made the published equations look as
though the V3/V3 multiplier was special to
the velocities they measured, whereas it was simply
a convenient choice from a literally infinite
variety of choices they could have made. G+O made it
even more confusing in the publication by using the
Newton dotty notation, which made it look as though
there was something necessary about the time
differentiation in the curvature equation.

                                  When we put all this

together, we come to the way this is a variant of
the “divide by zero” error. That error depends on
the fact that you can put any variable at all in for
“x” in “x/0 = infinity”. The – shall we call it –
the “curvature error” depends on the fact that you
can use anything at all for V (including the
measured values), provided only that V is defined as
ds/dz where z is some variable for which ds/dz
exists everywhere. You therefore cannot use the
curvature equation in any way to determine V.

              Does this "Sunday" explanation help?
              RM: Not really. Are you saying that G+O used the

wrong formulas for V and R? Or that the formulas they
published are not actually the ones they used to
compute V and R? Or that there is no way to compute R
since we can’t measure ds? Either way, you can’t say I
made a math error since I did the math correctly on
the formulas I was given. (And, as I mentioned, the
results came out exactly right).

                      MT: but the critical

point of my suggestion that you read my
earlier message is contained in this:

RM: Contained in what?

              RM: Rather than saying that I was making a math

error, it would have helped if you had just said:
“these are the correct formulas for computing V and R”
and showed me the formulas.

              That would have saved a lot of trouble. So how

about it; what are the correct formulas for computing
V and R?

Best

Rick


Richard S. Marken

                                      "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand
that what they do for
others is just as important to
their well-being as what they
do for
themselves." – William T.
Powers


Richard S.
Marken

                                                "The childhood of

the human race is
far from over. We
have a long way to
go before most
people will
understand that what
they do for
others is just as
important to their
well-being as what
they do for
themselves." –
William T. Powers

[From Bruce Abbott (2016.09.14.1105 EDT)]

Rick Marken (2016.09.13.1610) –

MT: but the critical point of my suggestion that you read my earlier message is contained in this:

RM: Contained in what?

RM: Rather than saying that I was making a math error, it would have helped if you had just said: “these are the correct formulas for computing V and R” and showed me the formulas. That would have saved a lot of trouble. So how about it; what are the correct formulas for computing V and R?

BA: I would disagree with Martin a little by saying that the error you are making is not a math error (solving for V in the formula for R does follow the rules of algebra). It is a logical or conceptual error.

BA: The problem is that this error has been explained to you several times, in various ways, under the assumption that you do want to understand the problem and simply need a clear explanation of it. I will give it one last try. Let’s start with this diagram from https://en.wikipedia.org/wiki/Curvature :

image00265.png

Here we have a curvy line C.  At point P an “osculating circle� has been fit such that the curvature of the circle best matches the curvature of the line at point P. This circle has radius r. The mathematical problem is to find the value of r.

You need calculus to solve this problem, because we want the instantaneous value of r at point P. We have to imagine moving a tiny fixed distance s along the curve, beginning at P. Call the new position P’. If we moved this distance in time dt, we could specify this distance as the tangential velocity V of a point moving along curve C, multiplied by dt. (V = ds/dt; ds = V*dt)

                                                                                                                                                                                                           Â

We can decompose this tangential motion into its Cartesian X and Y coordinates to yield the changes in X and Y as we move along the curve from P to P’. If you wish, you can think of X and Y as velocities with respect to time:  dX/dt and dY/dt. We can also find the rates at which these velocities are changing, dX/dt2 and dY/dt2. As we move along a circle, the velocities of X and Y change in a systematic way. For example., if we were moving counterclockwise along the bottom of the circle, X would increase much faster than Y, but as we continued along the circle we would be moving more and more in the vertical direction and less and less in the horizontal direction. X would be decelerating and Y accelerating. Exactly how one changes with respect to the other, at a given tangential velocity, tells us what the arc of the circle is, and from that we can compute the circle’s radius.

The equation for R takes into account both the instantaneous tangential velocity of motion along the arc and the instantaneous changes in velocity in the X and Y coordinate directions. The top of the equation specifies the cube of the tangential velocity. The bottom specifies the cross-products of the velocity of X times the acceleration of Y plus the velocity of Y times the acceleration of X. When you do the division, time drops out and you are left with a pure distance: the radius R.

Now here is the important part, the part you have been missing. Velocity in terms of distance/time is only a convenient way to get a distance along the arc. We could just as easily have used distance along the arc per unit of change in the angle of the tangent to the circle (the straight line passing through P in the above diagram). The result will be the same either way. But we are already measuring velocity/time (V) from the data when doing the power-law computations, so it is convenient to base the calculation of R on time-based velocities and accelerations.

Thus, the V used in the computation of R (together with the time-based velocities and accelerations found in the denominator) only serve to determine, at a given instant in time, the curvature of the arc.

If one solves the R formula for V, you will only see what the tangential velocity was that went into the computation of R at a certain point along the curve. At that same moment, the velocities and accelerations used in the denominator of the equation will also have specific values that depend on the curvature of the line at that point. It is the ratio of these changes that determines the value of R at that point. The two will be in a certain fixed relation that depends on the curvature of the arc along which the point is traveling.

The fact that, at a given point, V is a certain value when R was computed, does not imply that V and R must be in the same fixed relation from one moment to the next. The idea that they must be is the fallacy you commit in your analysis.

To see that this is true, imagine a point moving along a perfect circle at a tangential velocity that varies from moment to moment. At each given moment, V will have a particular value, and so will the values of velocity and acceleration that go into the denominator of the equation for R. Dividing V-cubed by this denominator will yield a particular value for R, the radius of the circle. As V changes moment by moment, so will the denominator, and it will change in such a way that the computed R will remain the same. No matter what value V takes on, R will not vary because (a) the point is still traveling around the same circle of radius R, and (b) the velocities and accelerations that appear in the denominator of the formula will change with V in such a way as to keep R fixed.

Clearly then, V can be any value, no matter what the radius of the circle along which a point is traveling. V and R both can change across repeated observations as the point moves, and can do so in any imaginable relationship. V could increase while R decreases, or vice versa, to give just two examples. What holds at each instant in time (the value of R determined by the values of V and the denominator) does not imply anything as to what will hold across time (how V will as a function of R).

Like Martin, I have reluctantly come to believe that you are not really interested in understanding all this. Apparently, the idea that you have discovered a new form of the “behavioral illusion� is just too seductive an idea to give up, and being a good control system, you have been using all the methods at your disposal to resist having to admit that your analysis is just an embarrassing mistake. Prove me wrong: show me that you understand the above, even if you do not agree with it. Restate it in your own words.

Bruce

image00176.png

[From Rick Marken (2016.09.14.0845)]

···

On Wed, Sep 14, 2016 at 1:52 AM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

AGM: In other words, join me in the efforts of these newly created and much needed ONG:

www.pleaseStopRCP.org

(RCP = Rhetoric Control Theory)

RM: I presume you are implying that my PCT explanation of the power law is all “rhetoric”. That strikes me as odd since I have produced a PCT model, tested it against data and showed how it accounts for the power law; while all the “non-rhetorical” PCT side has produced is, well, rhetoric (mainly having to do with how my math is wrong and that the power law “suggests” the existence of some unspecified controlled variable). Until I see your PCT model that accounts for the existence of the power I think all that needs to be posted at the StopRCP site is the arguments of the ostensibly non-rhetorical PCT side of the discussion.

Best

Rick

On Wed, Sep 14, 2016 at 8:38 AM, Alex Gomez-Marin agomezmarin@gmail.com wrote:

martin, the csgNet is now a hybrid of a basic math accademy with an entertainment program for writing and joking with those who write back. stay tuned!

On Wednesday, 14 September 2016, Martin Taylor mmt-csg@mmtaylor.net wrote:

[Martin Taylor 2016.09.13.22.49]

[From Rick Marken (2016.09.13.1610)]

If you actually read and thought about what you quote, I cannot read

your question as anything other than a not too subtle joke, so I
have to assume that you either did not read it or the maths, which I
tried to explain at the most basic level O could manage without
seeming to insult you (which I was afraid I was doing anyway), was a
bit too deep for you.

 Isuggest you try again, concentrating on figuring out why this DOES

explain why you have been making the same kind of mistake as the
“divide by zero” error. Perhaps I should repeat the last lines: " When we put all this together, we come to
the way this is a variant of the “divide by zero” error. That
error depends on the fact that you can put any variable at all in
for “x” in “x/0 = infinity”. The – shall we call it – the
“curvature error” depends on the fact that you can use anything at
all for V (including the measured values), provided only that V is
defined as ds/dz where z is some variable for which ds/dz exists
everywhere. You therefore cannot use the curvature equation in any
way to determine V."

  I emphasize "IN ANY WAY". Since I may be a little too subtle when

I say this, it simply says that your equation V = D1/3*C1/3 means
nothing at all, because it is true when V is any variable at all
that satisfies a very loose condition. If it is a velocity it can
be any velocity at all, or it can be any value of any variable
(and here I will repeat myself) that depends on any other variable
“z” whatever for which ds/dz is everywhere calculable.

G+O showed the correct formulas, and I said so. You did the correct

FORMAL algebra. Your math error was and apparently continues to be
the equivalent of the “divide by zero” error, which also depends on
doing the algebra correctly. The “divide by zero” or its “curvature
error” equivalent is a math error if ever there was one. It could be
and should be easily correctable, but apparently it isn’t. I don’t
know why.

Martin

RM: Oh, I see. It’s contained in this:

                MT: Now we have to see how

they came to equation (9). That’s a bit more
complicated, so please bear with me.

                                  MT: They presumably

either used someone else’s derivation or made their
own, starting from one of several equivalent
measures of curvature, one of which is C = 1/R where
R is the radius of the osculating circle at the
point of concern. Another one is developed using
vector calculus, which I have no intention of
introducing into this discussion. It is C = dx/dsd2y/ds2 - dy/ds * d2x/ds2 , where s is distance along
the curve from some arbitrary starting point.
For G+O this formula
was not very convenient, because they would have had
to measure these first and second derivatives of x
and y with respect to distance along the curve
fairly accurately. But they had a trick available,
in the “chain rule” of differentiation: dx/dy
dy/dz
= dx/dz. The "dy"s cancel out just like ordinary
variables. Using the chain rule on the first
derivative gives you the rule for the second
derivative, and so on. For the second derivative the
rule is (d2x/dy2)(dy/dz)2 = d2x/dz2.
Using the chain rule,
G+O could multiply the formula for C by (ds/dz}3/(ds/dz)3 = 1, for any variable z
that allowed the differentiation, to get C =
((dx/ds)
(ds/dz)(d2y/ds2)(ds/dz)2)(ds/dz)3 - (dy/ds)(ds/dz)(d2x/ds2)__(ds/dz)__3)/(ds/dz)3 . This formula is true
(allowing for typos) for variable “z” whatever (as
with the divide by zero example), but it wouldn’t
have helped G+O very much, had it not been that for
one particular variable they already had measures
they could use. Those measures were the ds/dt
velocity and the derived d2s/dt2 values they had obtained
from their observations of movement. Using those
measures, they could set “z” = t (time), making
dx/dt = dx/ds*ds/dt. They could then take advantage
of their measured velocities to substitute for
ds/dt, and write

              C = (dx/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup> - (dy/dt*d<sup>2</sup>y/dt<sup>2</sup>)/V<sup>3</sup>

                                  Oh goody! We don't have

to measure anything new to get our curvatures. We
can use the values of dx/dt and dy/dt that we got
before! Very handy. … But also very confusing,
because it made the published equations look as
though the V3/V3 multiplier was special to
the velocities they measured, whereas it was simply
a convenient choice from a literally infinite
variety of choices they could have made. G+O made it
even more confusing in the publication by using the
Newton dotty notation, which made it look as though
there was something necessary about the time
differentiation in the curvature equation.

                                  When we put all this

together, we come to the way this is a variant of
the “divide by zero” error. That error depends on
the fact that you can put any variable at all in for
“x” in “x/0 = infinity”. The – shall we call it –
the “curvature error” depends on the fact that you
can use anything at all for V (including the
measured values), provided only that V is defined as
ds/dz where z is some variable for which ds/dz
exists everywhere. You therefore cannot use the
curvature equation in any way to determine V.

              Does this "Sunday" explanation help?
              RM: Not really. Are you saying that G+O used the

wrong formulas for V and R? Or that the formulas they
published are not actually the ones they used to
compute V and R? Or that there is no way to compute R
since we can’t measure ds? Either way, you can’t say I
made a math error since I did the math correctly on
the formulas I was given. (And, as I mentioned, the
results came out exactly right).

                      MT: but the critical

point of my suggestion that you read my
earlier message is contained in this:

RM: Contained in what?

              RM: Rather than saying that I was making a math

error, it would have helped if you had just said:
“these are the correct formulas for computing V and R”
and showed me the formulas.

              That would have saved a lot of trouble. So how

about it; what are the correct formulas for computing
V and R?

Best

Rick


Richard S. Marken

                                      "The childhood of the human

race is far from over. We
have a long way to go before
most people will understand
that what they do for
others is just as important to
their well-being as what they
do for
themselves." – William T.
Powers


Richard S.
Marken

                                                "The childhood of

the human race is
far from over. We
have a long way to
go before most
people will
understand that what
they do for
others is just as
important to their
well-being as what
they do for
themselves." –
William T. Powers

Richard S. Marken

“The childhood of the human race is far from over. We
have a long way to go before most people will understand that what they do for
others is just as important to their well-being as what they do for
themselves.” – William T. Powers