[From Bjorn Simonsen (2010. 12.03, 22:55 EU ST)]
[From Rick Marken (2010.12.03.1125)]
I don’t know if I understand what you are thinking. But let me take a stab at it. The outputs
(O cells) at each level in hier.exl are the output signals (efferent neural signals) from each
control system at that level.
If that is correct, you have answered my problem which was not a problem. But…
Let me take an example from your hier.exl.
**System **
1
2
3
4
5
6
Average
Level
*=imagine
Error
Slowing
Gain
R(3,i)
1,00
1,00
1,00
1,00
1,00
1,00
3
P(3,i)
-1,00
-1,00
1,00
1,00
1,00
-1,00
1,000
Error
0,0001
1000
O(3,i)
30,60
26,94
23,05
32,00
39,19
49,31
*=imagine
R(2,i)
10,00
6,00
-3,89
8,95
7,19
10,12
2
P(2,i)
7,99
7,99
8,55
-1,62
-2,65
-3,16
8,358
Error
0,0001
500
O(2,i)
14,77
-6,82
-49,70
48,90
44,02
51,26
*=imagine
R(1,i)
7,95
1,50
4,63
-13,55
0,09
15,99
1
P(1,i)
7,99
2,34
5,07
-12,82
0,31
14,79
0,579
Error
0,01
50
O(1,i)
-2,01
9,86
-21,02
-28,56
-11,16
18,96
System
CV
Q(i)
7,99
2,29
5,07
-12,89
0,43
14,97
3,312
Disturbance
D(i)
10,00
-7,09
26,09
15,62
11,66
-4,24
Behavior
-33,93
**Disturbance **
Cycle
20
Level 2 R(2,6) 10,12. The formula here is I5 - H5 (49.31 - 39.19). Or as you say:
The reference signals (the R cells in the systems below the O cells at each level, except level
- are the properly combined outputs from the relevant O cells in the next level up; properly
combined in the sense that an output is combined into a lower level reference only if the
perception from that lower level system contributes to the perception of the higher level system
from whence that output comes, and with the opposite sign.
But if you read BCP page 286, you see
- q(o) = k(o)* e and six lines above, k(o) has units of (other) physical units per signal unit. How can q(o) be:
The outputs (O cells) at each level in hier.exl are the output signals (efferent neural signals) from each
control system at that level.
I think e is an efferent neural signal and when you multiply it with k(o) which has units of (other) physical units per signal unit it can’t still be a neural signal.
Of course I know I think the wrong way. and you the correct way. But I can’t see where I think wrong.
bjorn