RM: I know. And you have the same problem in your responding to my criticism.
I don’t think I have seen you criticizing my arguments by showing what is wrong with them, by showing contradictions in or faulty premises and inferences. You just keep repeating your views and stating that because I disagree I am wrong.
RM: That’s because we, like all living things, are controllers, in fact, not just in theory.
No, we certainly are controllers but that does not mean that we must control for being always and absolutely right. We can also control for finding truth and it is possible only if we do not control for being already right. You are controlling for knowing the final truth about the power law phenomenon but I am not. I admit that I have only very vague hypotheses about it. I am sure only about one thing: that there are essential errors in your argumentation.
RM: …Affine velocity is not an “extra” predictor. It is one of the variables in the mathematical relationship between the measures of curvature and velocity that are used in determining whether or not there is a -1/3 power relationship between these measures.
No, the fact that both velocity and curvature can be measured from the same time based coordinate data of x and y positions and that there are similarly looking parts in both equations does not create a mathematical relationship between them. This should be clear because first the velocity and curvature can be measured also differently: Time is not needed to measure the curvature. Secondly exactly the same curvature can be moved through with different velocities, also with a stable velocity (=no correlation between curvature and velocity). So the velocity does not affect the measure of curvature (and in another way around) – even if they were measured from the same position data. So there is no mathematical relationship between velocity and curvature, even though there of course is mathematical relationship between the three variables. This has been told you at least ten times but you have never shown what is wrong in this.
RM: My argument is that the measurement method – calculating velocity and curvature from the same movement trajectory-- and the analysis method – simple linear regression – have “created” the power law phenomenon.
What you mean by “created” (in quotes)? Are we in the beginning of the dispute: that power law phenomenon is a bogus phenomenon, an illusion, a mirage, created by the researchers but not existing in reality? Do you meant that when a hand, a larva, a person or a helicopter moves along a curved trajectory, there is not a correlation between the velocity and curvature, and the velocity is not (sometimes or often) decreasing when the curvature is increasing, and there is not (sometimes or often) a power relationship between the velocity and curvature?
RM: OK, so you agree now that my equation: … is, indeed, exactly the same as the one derived by Moaz et al.
No one has ever denied that. The problem is not there. The problem is that from those equations does not follow what you claim and what Maoz et al possibly thought.
EP: The problem is that we can derive (or devise) an infinite amount of valid mathematical equations but it is totally a different question to what tasks they can be applied.
RM: I don’t understand what this means. Could you give me an example of some small subset of equations from that " infinite amount of valid equations".
I have already done that earlier but probably you have not read it - at least very carefully. All the equations of the form C^x * V^y = Z are mathematically as valid. And by using Z as an extra predictor in your “OVB” regression analysis you will get as many different power coefficients – and fake mathematical relationships – between C and V as you wish to. What is more important – let’s say it again – is that C and V need not even be the curvature and the velocity of any trajectory. As we have shown by the spreadsheets they can be any random variables which have no internecine correlation, and still your “OVB” analysis creates a fake mathematical relationship between them. What could be stronger evidence of a faulty method and mistaken mathematical reasoning?
EP: Maoz et al (2006) did apply that equation by deriving further an equation (6) [β = −1/3 + ξ/3] where beta β is the linear regression coefficient of log(v) versus log(κ) and ξ (xi) is the linear regression coefficient of log(α) versus log(κ). From this they saw that: “Hence, if log(α) and log(κ) are statistically uncorrelated, the linear regression coefficient between them, which we termed ξ, would be 0, and thus from (6) the linear regression coefficient of log(v) versus log(κ), which we named β, would be exactly −1/3. Therefore, any trajectory that produces log(α) and log(κ) that are statistically uncorrelated would precisely conform to the power law in (1)” which they earlier termed as “the two-thirds power law”. In a footnote they say: “α being constant is naturally a special case of uncorrelated log(α) and log(κ).”
Now, what is wrong in above mathematical reasoning of Maoz et al?
RM: That’s what I’d like to know!!
Perhaps I did not say it clearly enough. The problem in the mathematical reasoning of Maoz et al seems to be that they did not see that in a trajectory where curvature varies the only possibility for uncorrelated log(α) and log(κ) is that alpha is stable. The more alpha varies the more there is correlation because alpha is mathematically determined as a multiplication product of curvature and velocity (or them to the powers).
RM: So you have clearly not shown that there is anything wrong with Moaz et al’s equation (4) (and M&S equivalent equation).
Oh no, how many times it must be said that there nothing wrong in that equation (per se), only in the inferences made from it.
EP: What about (6) and inferences from it? The core here is the question when does a trajectory produce log(α) and log(κ) that are statistically uncorrelated (which is the same that when does a trajectory obey the power law)?
RM: No, that is not the core question at all. The core question is “Does equation 6 correctly (and exactly) predict the value of the power coefficient of curvature (Beta) when affine velocity is omitted as a predictor variable”? And the answer, which is easily demonstrated computationally, is that it does.
I think it should not be any wonder that it does. I will simplify. Say that Z = X * Y. Now if there is a certain statistical relationship, let’s call it w, between X and Y then there certainly must be some similar kind of statistical relationship also between X and Z, say v, so that the relationship between w and v can be expressed by some mathematical equation. You can test this computationally, if you want. It would be nice to see that!
EP: Now we can go to the problem the “OVB analysis”.
RM: I think i’ll stop here. Based on what you’ve already said it is clear to me (but not to you) that you do not understand regression or OVB analysis, (or to be nicer about it, you don’t understand these analyses the way I do). So we’re really not going to get anywhere with this.
Dismissal again! Couldn’t you try to teach me, not by repeating yourself because repetition is not a good method to teach, but by showing what is wrong in my understanding? What is wrong in my example of a proper way to apply OVB to find extra variables which affect school success and salary level? What is wrong in my view that that a method which gives the same exact power coefficient to all possible pairs of random variables is quite uncredible?
Happy New Year!
Eetu